What is the length for the 3rd side? write in simplest radical form if needed

Mathematics

1 answer:

9966 [12]2 years ago

6 0

Answer:

Step-by-step explanation:

Using Pythagoras' identity in the right triangle.

Let the third side be x , then

x² + 6² = (2 $\sqrt{34}$ )²

x² + 36 = 136 ( subtract 36 from both sides )

x² = 100 ( take the square root of both sides )

x = $\sqrt{100}$ = 10

You might be interested in

HELP PLZ AGAIN. Same material. It is still timed. Will give 50 pts and brainly. This is vital to my math grade. Time is on the e

Sliva [168]

Answer:

slope-intercept form: y = x+2

The slope is 1

y-interspet is -2

Step-by-step explanation:

hope it helps

7 0

2 years ago

Sin theta+costheta/sintheta -costheta+sintheta-costheta/sintheta+costheta=2sec2/tan2 theta -1

sleet_krkn [62]

$\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}=\dfrac{2sec^2\theta}{tan^2\theta-1}$

From Left side:

$\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}\bigg(\dfrac{sin\theta+cos\theta}{sin\theta+cos\theta}\bigg)+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}\bigg(\dfrac{sin\theta-cos\theta}{sin\theta-cos\theta}\bigg)$

$\dfrac{sin^2\theta+2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}+\dfrac{sin^2\theta-2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}$