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GarryVolchara [31]
3 years ago
8

Which of the following expressions is equivalent to x+14−3x−27−11y

Mathematics
1 answer:
Mariana [72]3 years ago
5 0

Answer:

The answer is D)-2x-11y-13

Step-by-step explanation:

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What is 2000000000+ 3000000000
Rom4ik [11]

Answer:

Hope this helps

Step-by-step explanation:

5000000000

4 0
3 years ago
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Solve this pls<br><br> 6i&lt;5i+3u
lions [1.4K]

i < 3u

Step-by-step explanation:

6i < 5i + 3u

6i - 5i < 3u

i < 3u

8 0
3 years ago
Drag the correct number of pieces to show how to find the area of the shaded figure in two different ways. Pieces can be rotated
AURORKA [14]

Answer:forgot to add sin a = -5

Step-by-step explanation:

3 0
3 years ago
Please answer this please
cluponka [151]

Step-by-step explanation:

<h3>1. x² + 4 = (x+2)² </h3>

<h3> : x² + 4 = x² + 4 (Yes)</h3>

<h3>2. (2x+6)²= 4(x+3)²</h3>

<h3> : 4x²+36 = 4x² + 36 ( Yes)</h3>

<h3>3. (x-3)(x-3)= (x-9)² (NO)</h3>

<h3>beacause , True statement is</h3><h3> (x+3)(x-3)= (x-9)²</h3>

<h3>4. x²-10x+25 = (x-5)(x+5) (No)</h3>

<h3> : x²-2x+y² = (a-b)(a+b) </h3>

<h3>Therefore, its not true statement!</h3>
4 0
3 years ago
The weights of newborn baby boys born at a local hospital are believed to have a normal distribution with a mean weight of 4016
hodyreva [135]

Answer:

Required Probability = 0.97062

Step-by-step explanation:

We are given that the weights of newborn baby boys born at a local hospital are believed to have a normal distribution with a mean weight of 4016 grams and a standard deviation of 532 grams.

Let X = weight of the newborn baby, so X ~ N(\mu=4016 , \sigma^{2} = 532^{2})

The standard normal z distribution is given by;

              Z = \frac{X-\mu}{\sigma} ~ N(0,1)

Now, probability that the weight will be less than 5026 grams = P(X < 5026)

P(X < 5026) = P( \frac{X-\mu}{\sigma} < \frac{5026-4016}{532} ) = P(Z < 1.89) = 0.97062

Therefore, the probability that the weight will be less than 5026 grams is 0.97062 .

5 0
3 years ago
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