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valentinak56 [21]
2 years ago
8

Which variable will you choose to eliminate? How?

Mathematics
1 answer:
Inga [223]2 years ago
4 0

Answer:

  • Variable elimination
  1. 8x+3y=-7
  2. 3y=-8x-7
  3. y=-8/3x-7/3
  • Now plug it into y
  • 7x-16/3x-14/3=-3
  • 5/3x-14/3=-3
  • 5/3x=5/3
  • x=1
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X squared minus 5x equals 0
Nadusha1986 [10]
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2 years ago
Question 4 of 10
Anvisha [2.4K]

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C

Step-by-step explanation:

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7 0
3 years ago
Find the area a of the triangle whose sides have the given lengths. a = 20, b = 15, c = 25 a =?
PIT_PIT [208]

The area of a triangle with sides a = 20, b = 15, and c = 25 is 150.

The sides of the triangle are given as a = 20, b = 15, and c = 25.

We will use Hero's formula to find the area of this triangle.

<h3>What is Heron's formula?</h3>

It is a three-face polygon that consists of three edges and three vertices.

We use Heron's formula to find the area of a triangle with 3 sides:

Herons formula:

Area of a triangle =  \sqrt{s(s-a)(s-b)(s-c)}\\

Where a, b, and c are sides of a triangle.

And s = semi perimeter of a triangle.

s = \frac{a+b+c}{2}

If the sum of two sides of a triangle is greater than the third side of a triangle then the sides of a triangle are true.

Let the given sides be:

a = 20, b = 15 and c = 25.

(20 + 15) > 25

(20 + 25) > 15

(15 + 25) > 20 so the given sides are true.

Now,

Semi perimeter of the triangle:

s = (a+b+c) / 2

s = (20+15+25) / 2

s = 60 / 2

s = 30

Putting s = 30 in the area of the triangle.

we get,

Area of the triangle = \sqrt{s(s-a)(s-b)(s-c)}\\

Area of the triangle = \sqrt{30(30-20)(30-15)(30-25)}\\\\\sqrt{30\times10\times15\times5}\\\\\sqrt{22500}\\\\150

Thus, the area of a triangle is 150.

Learn more about the Area of triangles here:

brainly.com/question/11952845

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3 0
2 years ago
Find the lateral area of the regular pyramid<br><br> L.A. =
Arisa [49]

Answer:

FOR REGULAR PYRAMID with those dimension.

L.A = 96

FOR HEXAGONAL PYRAMID with those dimension

L.A = 171.71

Step-by-step explanation:

Please the question asked for L.A of a REGULAR PYRAMID, but the figure is a HEXAGON PYRAMID.

Hence I solved for both:

FOR REGULAR PYRAMID

Lateral Area (L.A) = 1/2* p * l

Where p = Perimeter of base

P = 4s

P = 4 * 6

P = 24cm

l = slanted height

l = 8cm

L.A = 1/2 * 24 * 8

L.A = 1/2 ( 192)

L.A = 96cm ^ 2

FOR AN HEXAGONAL PYRAMID

Lateral Area = 3a √ h^2 + (3a^2) / 4

Where:

a = Base Edge = 6

h = Height = 8

L.A = 3*6 √ 8^2 + ( 3*6^2) / 4

L.A = 18 √ 64 + ( 3 * 36) / 4

L.A = 18 √ 64 + 108/4

L.A = 18 √ 64+27

L.A = 18 √ 91

L.A = 18 * 9.539

L.A = 171.71

8 0
3 years ago
The midpoint of VW is M(2, 4). One endpoint is W(1, 7). Find the coordinates of the other endpoint V.
kkurt [141]

Answer:

V(3, 1)

Step-by-step explanation:

4 0
3 years ago
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