Question

mips Write a program that asks the user for an integer between 0 and 100 that represents a number of cents. Convert that number of cents to the equivalent number of quarters, dimes, nickels, and pennies. Then output the maximum number of quarters that will fit the amount, then the maximum number of dimes that will fit into what then remains, and so on. If the amount entered is negative, write an error message and quit. Amounts greater than 100 are OK (the user will get many quarters.) Use extended assembly instructions and exception handler services.

Answer 1

Answer:

Explanation:

The following code is written in python and divides the amount of cents enterred in as an input into the correct amount of quarters, dimes, nickels and pennies. Finally, printing out all the values.

import math

#First we need to define the value of each coin

penny = 1

nickel = 5

dime = 10

quarter = 25

#Here we define the variables to hold the max number of each coin

quarters = 0

dimes = 0

nickels = 0

pennys = 0

cents = int(input("Please enter an amount of money you have in cents: "))

if cents > 0 and cents <= 100:

   if cents >= 25:

       quarters = cents / quarter

       cents = cents % quarter

   if cents >= 10:

       dimes = cents/dime

       cents = cents % dime

   if cents >= 5:

       nickels = cents /nickel

       cents = cents % nickel

   if cents > 0:

       pennys = cents / penny

       cents = 0

   print("The coins are: "

       "\nQuarters", math.floor(quarters),

       "\nDimes", math.floor(dimes), "\nNickels", math.floor(nickels), "\nPennies", math.floor(pennys))

else:

   print("wrong value")