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lana66690 [7]
2 years ago
6

The graph of y = x(x + 1)(x - 1)(x - 3) is shown.

Mathematics
1 answer:
vaieri [72.5K]2 years ago
6 0
B because a turning point of the graph means the valley or the top of a period of graph, the slope of the tangent line of which turn from negative to positive or from positive to negative.
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5y+1=1<br> Subtract 1 from both sides
maks197457 [2]

Step-by-step explanation:

5y + 1 = 1 \\ subtracting \: 1 \: from \: both \: sides \\ \red{ \boxed{ \bold{ 5y + 1 - 1 = 1 - 1}}} \\ 5y = 0 \\ y = 0

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the perimeter of a rectangle poil is 72 feet. the length of pool is 4 ft. more than three times the width. what is the length an
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Did I do my math homework right?
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What eigen value for this matix <br> (1 -2)<br> (-2 0)
natali 33 [55]

You find the eigenvalues of a matrix A by following these steps:

  1. Compute the matrix A' = A-\lambda I, where I is the identity matrix (1s on the diagonal, 0s elsewhere)
  2. Compute the determinant of A'
  3. Set the determinant of A' equal to zero and solve for lambda.

So, in this case, we have

A = \left[\begin{array}{cc}1&-2\\-2&0\end{array}\right] \implies A'=\left[\begin{array}{cc}1&-2\\-2&0\end{array}\right]-\left[\begin{array}{cc}\lambda&0\\0&\lambda\end{array}\right]=\left[\begin{array}{cc}1-\lambda&-2\\-2&-\lambda\end{array}\right]

The determinant of this matrix is

\left|\begin{array}{cc}1-\lambda&-2\\-2&-\lambda\end{array}\right| = -\lambda(1-\lambda)-(-2)(-2) = \lambda^2-\lambda-4

Finally, we have

\lambda^2-\lambda-4=0 \iff \lambda = \dfrac{1\pm\sqrt{17}}{2}

So, the two eigenvalues are

\lambda_1 = \dfrac{1+\sqrt{17}}{2},\quad \lambda_2 = \dfrac{1-\sqrt{17}}{2}

5 0
2 years ago
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Answer:

14

Step-by-step explanation:

In 70/5 the dividend is 70 and the divisor is 5 .

First draw a number line from zero to the dividend.

Next, starting from 70 skip count by the divisor backwards till you reach 0.

The numbers of skips taken to reach zero is the result, also called, the quotient. In this case there are 14 skips .

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