95% of red lights last between 2.5 and 3.5 minutes.
<u>Step-by-step explanation:</u>
In this case,
- The mean M is 3 and
- The standard deviation SD is given as 0.25
Assume the bell shaped graph of normal distribution,
The center of the graph is mean which is 3 minutes.
We move one space to the right side of mean ⇒ M + SD
⇒ 3+0.25 = 3.25 minutes.
Again we move one more space to the right of mean ⇒ M + 2SD
⇒ 3 + (0.25×2) = 3.5 minutes.
Similarly,
Move one space to the left side of mean ⇒ M - SD
⇒ 3-0.25 = 2.75 minutes.
Again we move one more space to the left of mean ⇒ M - 2SD
⇒ 3 - (0.25×2) =2.5 minutes.
The questions asks to approximately what percent of red lights last between 2.5 and 3.5 minutes.
Notice 2.5 and 3.5 fall within 2 standard deviations, and that 95% of the data is within 2 standard deviations. (Refer to bell-shaped graph)
Therefore, the percent of red lights that last between 2.5 and 3.5 minutes is 95%
Answer:
Step-by-step explanation:
One of the cars are blue. it can travel 31 1/2 miles on 1 1/4 gallons of gasoline. Converting 31 1/2 miles to decimal, it becomes 31.5 miles. Converting 1 1/4 gallons of gasoline to decimal, it becomes 1.25 gallons of gasoline.
Therefore, the miles per gallon for the blue car is
31.5/1.25 = 25.2 miles per gallon.
Another car is red it can travel 28 4/5 miles on 4/5 gallon of gasoline.
Converting 28 4/5 miles to decimal, it becomes 28.8 miles. Converting 4/5 gallons of gasoline to decimal, it becomes 0.8 gallons of gasoline.
Therefore, the miles per gallon for the red car is
28.8/0.8 = 36 miles per gallon.
X is 19
Explanation: because the opposite side of the angle is 134 degrees the other side also has to be 134 degrees. So we do 134-20 which is 114 and then 114 divided by 6 because the number next to x is 6 and the number that is x has to be 19 as 19x6 is 114.
I think this is the right answer and I hope it helps :)
This question is incomplete. The attached image was obtained online
Answer:
41 square units
Step-by-step explanation:
Looking at diagram that was attached, we can see that the Polygon s the combination of a square and a triangle.
In square CDEF we have:
The lengths of the side of the square= 4 units
Hence, the area of square is: length ²
Area of square= 4²
=16 square units
Also, in ΔBFA we have:
The base of the triangle is calculated as
=6 + 4= 10 units
height of the triangle is: FA= 5 units
The formula for Area of a triangle = 1/2 × Base × Height
Hence, we have area of ΔBFA as:
= 1/2 × 10 × 5
Area= 25 square units
The Area of the Polygon = Area of the square + Area of the triangle
16 square units + 25 square units
= 41 square units
IT WOULD BE "D" I BELIEVE
HOPE IM RIGHT AND THIS HELPS
