Answer: 65.7 gram
Explanation:
To calculate the moles :

According to stoichiometry :
1 mole of
are produced by = 2 moles of 
Thus 0.219 moles of
will be produced by =
of 
Mass of 
Thus 65.7 g of NaI, must be used to produce 55.6 g of iodine
Explanation:
Note: Molar masses of elements can be found online or in the periodic table.
Moles of Magnesium
= 3.60g / (24.3g/mol) = 0.148mol.
Moles of Chlorine
= 10.65g / (35.45g/mol) = 0.300mol.
Mole ratio of Magnesium to Chlorine
= 0.148mol : 0.300mol = 1 : 2.
Hence we have the empirical formula MgCl2.
Moles of Lithium
= 9.1g / (6.94g/mol) = 1.311mol.
Moles of Oxygen
= 10.4g / (16g/mol) = 0.650mol.
Moles ratio of Lithium to Oxygen
= 1.311mol : 0.650mol = 2 : 1.
Hence we have the empirical formula Li2O.
Answer:
Outside air
Nose
Lungs
Bloodstream
Cell
Explanation:
We breathe in oxygen from the outside air in through our nose and it travels to our lungs. Inside our lungs, we have Avioli's that diffuse oxygen into our bloodstream and the bloodstream helps the oxygen travel into our cells.
Hope this helps :)