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3 years ago

What evidence supports a conservation law?

Chemistry

1 answer:

True [87]3 years ago

3 0

Answer:

The answer is B.

Explanation:

The law of conservation of mass states that mass in an isolated system is neither created nor destroyed by chemical reactions or physical transformations.

According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.

The law of conservation of mass is useful for a number of calculations and can be used to solve for unknown masses, such the amount of gas consumed or produced during a reaction.

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Iodine is prepared both in the laboratory and commercially by adding Cl2(g) to an aqueous solution containing sodium iodide: 2Na

Oxana [17]

Answer: 65.7 gram

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

$\text{Moles of} I_2=\frac{55.6g}{254g/mol}=0.219moles$

$2NaI(aq)+Cl_2(g)\rightarrow I_2(s)+2NaCl(aq)$

According to stoichiometry :

1 mole of $I_2$ are produced by = 2 moles of $NaI$

Thus 0.219 moles of $I_2$ will be produced by = $\frac{2}{1}\times 0.219=0.438moles$ of $NaI$

Mass of $NaI=moles\times {\text {Molar mass}}=0.438moles\times 150g/mol=65.7g$

Thus 65.7 g of NaI, must be used to produce 55.6 g of iodine

8 0

3 years ago

Choose the correct word that describes the description. If you add too much sugar to the water, some of the crystals will sit on

Triss [41]

Answer:

saturated

Explanation:

7 0

2 years ago

Calculate the empirical formula of each of the following substances with the following compositions.

OleMash [197]

Explanation:

Note: Molar masses of elements can be found online or in the periodic table.

Moles of Magnesium

= 3.60g / (24.3g/mol) = 0.148mol.

Moles of Chlorine

= 10.65g / (35.45g/mol) = 0.300mol.

Mole ratio of Magnesium to Chlorine

= 0.148mol : 0.300mol = 1 : 2.

Hence we have the empirical formula MgCl2.

Moles of Lithium

= 9.1g / (6.94g/mol) = 1.311mol.

Moles of Oxygen

= 10.4g / (16g/mol) = 0.650mol.

Moles ratio of Lithium to Oxygen

= 1.311mol : 0.650mol = 2 : 1.

Hence we have the empirical formula Li2O.

7 0

2 years ago

Order the terms according to the path followed by oxygen during cellular respiration.

MArishka [77]

Answer:

Outside air

Nose

Lungs

Bloodstream

Cell

Explanation:

We breathe in oxygen from the outside air in through our nose and it travels to our lungs. Inside our lungs, we have Avioli's that diffuse oxygen into our bloodstream and the bloodstream helps the oxygen travel into our cells.

Hope this helps :)

8 0

2 years ago

Yo answer my question

igomit [66]

Answer:

C maybe

Explanation:

3 0

3 years ago

Read 2 more answers