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solniwko [45]
3 years ago
11

Jacinta has 2 blue marbles , 4 red marbles and 5 green marbles in a bag, all the marbles are the same size, she will select one

marbles from the marble from the bag without looking what is the possibility that Jacinta will choose the green marble
Mathematics
2 answers:
baherus [9]3 years ago
7 0

Jacinta has 2 blue marbles , 4 red marbles and 5 green marbles in a bag, all the marbles are the same size, she will select one marbles from the marble from the bag without looking what is the possibility that Jacinta will choose the green marble

cricket20 [7]3 years ago
7 0

Answer: 13/17 I'm pretty sure

Step-by-step explanation:

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Q= 4(a+b) solve for d
alukav5142 [94]

Answer:

b=  \frac{q - 4a}{4}

Step-by-step explanation:

ill suppose that you mean : "solve for b" not for d, since there is no d term in the formula given. So:

q = 4(a + b) \\ q = 4a + 4b \\ 4a + 4b = q \\ 4a + 4b - 4a = q - 4a \\ 4b = q - 4a \\ b =  \frac{q - 4a}{4}

7 0
2 years ago
Emery makes 8 necklaces and 3 bracelets, using a total of 172 beads. Then she makes 1 more necklace and 5 more bracelets, using
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15 beads per bracelet

Step-by-step explanation:

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3 years ago
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Amiraneli [1.4K]
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I send you a file wich the answer. 

4 0
3 years ago
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91 is 130% of what number w?​
Nitella [24]

Answer:

70

Step-by-step explanation:

91 ÷ 1.3 = 70

5 0
3 years ago
the equation a=1/2(b1+b2)h can be used to determine the area, a, of a trapezoid with height, h, and base lengths, b1 and b2. whi
galina1969 [7]

Answer:

b₁ = (2a – b₂h)/h; b₁ = (2a)/h – b₂; h = (2a)/(b₁ + b₂)

Step-by-step explanation:

A. <em>Solve for b₁ </em>

          a = ½(b₁ + b₂)h        Multiply each side by 2

        2a = (b₁ + b₂)h           Remove parentheses

        2a = b₁h + b₂h           Subtract b₂h from each side

2a - b₂h = b₁h                    Divide each side by h

         b₁ = (2a – b₂h)/h     Remove parentheses

         b₁ = (2a)/h – b₂

B. <em>Solve for h </em>

2a = (b₁ + b₂)h     Divide each side by (b₁ + b₂)

 h = (2a)/(b₁ + b₂)

5 0
3 years ago
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