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kvasek [131]
3 years ago
12

WILL MARK BRSINLIEST ANSWER IF GOTTEN RIGHT

Mathematics
2 answers:
Marianna [84]3 years ago
8 0

Answer:

16.8km

Step-by-step explanation:

Arc length = 2πr(θ/360)

=2π(8)(120/360)

=16.7551608191

≈16.8km

Arte-miy333 [17]3 years ago
8 0

Answer:

16.8 km

Step-by-step explanation:

Arc length = 2πr (θ/360)

So plug in the values:

2π(8)(120/360)      =        16π(1/3)      =       16π/3

16.75516 ——————> 16.8 km

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What is the slope of the line x=6
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Express the product in simplest form.
Dmitry [639]

The product in simplest form is (x - 4)

<em><u>Solution:</u></em>

<em><u>Given expression is:</u></em>

\frac{8}{2x+8} \times \frac{x^2-16}{4}

We have to find the product in simplest form

In the given expression,

2x + 8 = 2(x+ 4)

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a^2-b^2=(a+b)(a-b)

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Substitute these in given expression

\frac{8}{2(x+4)} \times \frac{(x+4)(x-4)}{4}

Cancel the common factors,

\frac{8}{2(x+4)} \times \frac{(x+4)(x-4)}{4} = x - 4

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3 years ago
Solve for x 5x+7=9x-25
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6 0
4 years ago
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The function H(t) = −16t2 + 60t + 95 shows the height H(t), in feet, of a projectile after t seconds. A second object moves in t
EleoNora [17]
H(t) = -16t² + 60t + 95
g(t) = 20 + 38.7t

h(1) = -16(1²) + 60(1) + 95 = -16 + 60 + 95 = -16 + 155 = 139
h(2) = -16(2²) + 60(2) + 95 = -16(4) + 120 + 95 = -64 + 215 = 151
h(3) = -16(3²) + 60(3) + 95 = -16(9) + 180 + 95 = -144 + 275 = 131
h(4) = -16(4²) + 60(4) + 95 = -16(16) + 240 + 95 = -256 + 335 = 79

g(1) = 20 + 38.7(1) = 20 + 38.7 = 58.7
g(2) = 20 + 38.7(2) = 20 + 77.4 = 97.4
g(3) = 20 + 38.7(3) = 20 + 116.1 = 136.1
g(4) = 20 + 38.7(4) = 20 + 154.8 = 174.8

Between 2 and 3 seconds. 
The range of the 1st object is 151 to 131.
The range of the 2nd object is 97.4 to 136.1

h(t) = g(t) ⇒ 131 = 131

<span>It means that the point where the 2 objects are equal is the point where the 1st object is falling down while the 2nd object is still going up. </span>
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