True or false? When two objects interact, both force and motion are caused.

I really need to know what is on the physics SOL please someone tell me

lawyer [7]

The term sol is used by planetary astronomers to refer to the duration of a solar day on Mars.[7] A mean Martian solar day, or "sol", is 24 hours, 39 minutes, and 35.244 seconds.[6]

“Sol” is often used as a direct replacement for “Day” when concerning Mars. Mission duration for Mars missions is measured in Sols, so saying “Today is Sol xyz” would be normal, but I’m not sure if anyone would say “what a wonderful Sol tomorrow is going to be”.

5 0

4 years ago

What occurs as a ray of light passes from<br> al inilo water?

iVinArrow [24]

Answer:

this may be wrong but I am not sure

3 0

3 years ago

Suppose a 60-kg boy and a 41-kg girl use a massless rope in a tug-of-war on an icy, resistance-free surface. If the acceleration

Digiron [165]

Answer:

Approximately $2.05\; {\rm m\cdot s^{-2}}$ .

Explanation:

The net force on the girl would be:

$\begin{aligned}m(\text{girl}) \, a(\text{girl}) &= 41\; {\rm kg} \times 3.0\; {\rm m\cdot s^{-2}} \\ &= 123.0\; {\rm N} \end{aligned}$ .

Under the assumptions, the net force on this girl would be equal to the tension force in the rope. All other forces on the girl would be balanced.

In other words, the tension force that the rope exerted on the girl would be $123.0\; {\rm N}$ . The girl would exert a reaction force on the rope at the same magnitude ( $123.0\; {\rm N}\!$ ) in the opposite direction. This force would translate to a $123.0\; {\rm N}\!\!$ force on the boy towards the girl.

Under similar assumptions, the net force on the boy would also be $123.0\; {\rm N}$ . Since the mass of the boy is $m(\text{boy}) = 60\; {\rm kg}$ , the acceleration of the boy would be:

$\begin{aligned}a(\text{boy}) &= \frac{(\text{net force})}{m(\text{boy})} \\ &= \frac{123.0\; {\rm N}}{60\; {\rm kg}} \\ &= 2.05\; {\rm m\cdot s^{-2}}\end{aligned}$ .