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stich3 [128]
3 years ago
6

Suppose we replace the original launcher with one that fires the ball upward at twice the speed. We make no other changes. How f

ar behind the cart will the ball land, compared to the distance in the original experiment?
(A) half as far
(B)twice as far
(C) four times as far
(D) the same distance
(E) by a factor not listed above
Physics
1 answer:
expeople1 [14]3 years ago
5 0

Answer:

(C) four times as far

Explanation:

As we know that the range of the launcher is given as

R = \frac{v^2sin(2\theta)}{g}

here we know that all the parameters will remain same but only change is the velocity is doubled

So we will have

R' = \frac{(2v)^2 sin2\theta}{g}

so we have

R' = 4 R

so here correct answer will be

(C) four times as far

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The capacitor is now disconnected from the battery, and the plates of the capacitor are then slowly pulled apart until the separ
alexdok [17]

Answer:

U₁ = (ϵAV²)/6d

This means that the new energy of the capacitor is (1/3) of the initial energy before the increased separation.

Explanation:

The energy stored in a capacitor is given by (1/2) (CV²)

Energy in the capacitor initially

U = CV²/2

V = voltage across the plates of the capacitor

C = capacitance of the capacitor

But the capacitance of a capacitor depends on the geometry of the capacitor is given by

C = ϵA/d

ϵ = Absolute permissivity of the dielectric material

A = Cross sectional Area of the capacitor

d = separation between the capacitor

So,

U = CV²/2

Substituting for C

U = ϵAV²/2d

Now, for U₁, the new distance between plates, d₁ = 3d

U₁ = ϵAV²/2d₁

U₁ = ϵAV²/(2(3d))

U₁ = (ϵAV²)/6d

This means that the new energy of the capacitor is (1/3) of the initial energy before the increased separation.

3 0
3 years ago
Which statements about electric field lines are correct? Check all that apply.
pochemuha
They point towards a negative charge.
They point away from a positive charge.
They never cross.
3 0
3 years ago
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If the average pitcher is releasing the ball from a height of 1.8 m above the ground, and the pitcher's mound is 0.2 m higher th
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Answer: A. 2.0m above ground

Explanation:

Height of the pitcher from the floor of his mound = 1.8m

Height of the mound above the rest of the field = 0.2m

Since the height difference between the mound and the ground the catcher stands on = 0.2m and the pitcher throws the ball horizontally, then the catcher has to hold his glove at (1.8 + 0.2)m

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= 2.0m above ground (option A)

7 0
3 years ago
Pure science is best defined as the what?
WINSTONCH [101]

Answer:

A) continuing search for new knowledge

Explanation:

Science has always been about discovery and gaining knowledge

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A 310-N child is in a swing that is attached to a pair of ropes 2.10 m long. Find the gravitational potential energy of the chil
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Explanation:

Given that,

Force acting on the child, F = 310 N

Length of the ropes, d = 2.1 m

We need to find the gravitational potential energy of the child–Earth system relative to the child's lowest position when the ropes are horizontal. The potential energy is simply given by :

E=(mg)\times d\\\\E=F\times d\\\\E=310\ N\times 2.1\ m\\\\E=651\ J

Hence, this is the required solution.

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