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kherson [118]
3 years ago
8

Y=7x-3. y=-7x+3 What type of solution is this?

Mathematics
1 answer:
aivan3 [116]3 years ago
6 0
One solution: (3/7, 0)
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The first term of a sequence is -12. The recursive formula for the sequence is an = an-1 + 9. What are the next 3 terms in the s
Bess [88]
The next three terms are: -3, 6, and 15

To get each new term, we simply add 9 to the last term. So we add 9 to -12 to get -3. Then we add 9 to -3 to get 6. Finally we add 9 to 6 to get 15

In other words,
first term = -12
second term = first term+9 = -12+9 = -3
third term = second term + 9 = -3+9 = 6
fourth term = third term + 9 = 6+9 = 15

This process repeats forever though we only need three terms in this case.

So that's why the answer is the three values -3, 6 and 15
8 0
3 years ago
A fisher usually catches 540kg of anchovies off El Niño,the fisher caught 85% less fish. How many kilograms of fish did the fish
Nookie1986 [14]
The fisherman caught 365kg During El Niño. You subtract 540kg by 85.
7 0
3 years ago
Is the ordered pair
FrozenT [24]

Answer:

no, because for x=-3, y would have to be -31

Step-by-step explanation:

boy oh boy (or girl oh girl) - you wrote this in a horrible, horrible format.

I can only guess what your problem and the fitting answer would be.

y = -2×x^2 + 3×x - 4

-4 = -2×(-3)^2 + 3×(-3) - 4

-4 = -2×9 - 9 - 4

-4 = -18 - 9 - 4

-4 = -31

and that is wrong. for (-3,-4) to be on the graph of the function, y would have to be -4 when using x=-3 in the function. but y = -31 for x= -3.

8 0
3 years ago
Use the diagram to answer the question.
Aloiza [94]

Answer:

O lines and line t Intersect at Point P

5 0
2 years ago
Z=a/b+c/d solve for A
PilotLPTM [1.2K]

Answer: a=\frac{b(zd-c)}{d}

Step-by-step explanation:

Having the following equation given in the exercise:

z=\frac{a}{b}+\frac{c}{d}

You can solve for "a" following this procedure:

1. You can apply the Subtraction property of equality and subtract \frac{c}{d} from both sides of the equation:

z-(\frac{c}{d})=\frac{a}{b}+\frac{c}{d}-(\frac{c}{d})\\\\z-\frac{c}{d}=\frac{a}{b}

2. Now you must subtract the terms on the left side of the equation. Notice that the Least Common Denominator is "d". Then:

\frac{zd-c}{d}=\frac{a}{b}

3. Finally, you can apply the Multiplication property of equality and multiply both sides of the equation by "b". So, you get:

(b)(\frac{zd-c}{d})=(\frac{a}{b})(b)\\\\a=\frac{b(zd-c)}{d}

6 0
3 years ago
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