Y=7x-3. y=-7x+3<br><br> What type of solution is this?

Mindy was counting the money she received for her birthday. Her mom and dad gave her $50. From her aunt she received $16. From h

arlik [135]

44 molars she recieved is the range of mummy’s revived

5 0

3 years ago

A construction company is building a new parking garage and is charging the following rates: $5000 a month for the first 3 month

Elena L [17]

Answer:

C(t) = 5t for 0 < t ≤ 3

C(t) = (8t-9) for 3 < t ≤ 6

C(t) = 44 for 6 < t ≤ 10

C is given in thousands of dollars and t is given in months.

Total lump sum to be paid at the end of the 6 months for the total 10 months that the construction company works on the parking garage = $44000

Step-by-step explanation:

We will do a piecewise analysis for this cost function.

How to obtain the total cost changes with each time interval.

In the first 3 months,

C(t) = 5t for 0 < t ≤ 3

Note that C is given in thousands of dollars

In the next 3 months,

C(t) = (8t-9) for 3 < t ≤ 6

- Here, it gets a little complex, we use the upper limit of the previous interval and the lower limit of this new interval to get the constant to be subtracted from the normal 8t that characterizes this interval.

8(3) = 24

5(3) = 15

constant = 24 - 15 = 9

In the last 4 months,

C(t) = 44 for 6 < t ≤ 10

- For the last four months, it is a single sum of $5000 plus the [8(6) - 9] from the previous inteval

C = [8(6) - 9] + 5 = 39 + 5 = 44

So, the cost of parking, tracked month after month gives

T | Cost (in thousands of dollars)

1 | 5

2 | 10

3 | 15

4 | 23

5 | 31

6 | 39

7 | 44

8 | 44

9 | 44

10 | 44

Total lump sum to be paid at the end of the 6 months for the total 10 months that the construction company works on the parking garage = $44000

Hope this Helps!!!

8 0

3 years ago

HELP ME PLEASEEEEEEEEEE

Gekata [30.6K]

Area is 35
perimeter is 24

8 0

4 years ago

Find the equation of the line with y-intercept -2 and passing though the point (2,5). Show your work. What is the equation of a

mihalych1998 [28]

equation of a line with y intercept of neg.2 is y=mx-2

you could use pint slope[y-y1=m(x-x1)], but i preffer slope intercept form [y=mx+b]

5=m2-2

move 2 to the other side

7=m2

divide both sides by 2

3.5=m

so, the slope is 3.5

equation for a line that passes through point (2,5) with a y intercept of -2 is y=3.5x-2

the equation of a perpendicular line to the line y=3.5x-2 has a slope that is negative reciprical of 3.5

we keep the everything on y=3.5x-2 same except the slope.

negative reciprical slope of 3.5 is -

$- \frac{10}{35}$

simplify

$- \frac{2}{7}$

so, the equation of a line perpendicular to the first one is y=-2/7x-2

5 0

4 years ago

How do I Graph y=x−2

quester [9]

Answer:

go to graph go to -2 on vertical line (y axis) and then go up 1 right 1 place dot up 1 right 1 place dot go bac to -2 on vertical line (y axis) and go down 1 left 1 place a dot down 1 left 1 and place a dot you get now right

Step-by-step explanation:

3 0

3 years ago

Y=7x-3. y=-7x+3 What type of solution is this?