Minimum is (4,3) and Vertical intercept is (0,5) correct me if I’m wrong
Let Bea = x
Therefore Andrew = x + 2
Chris = x - 3
Andrew * Chris = 66
(x + 2)(x - 3) = 66 Remove the brackets.
x^2 + 2x - 3x - 6 = 66
x^2 - x - 6 = 66 Subtract 66 from both sides.
x^2 - x - 72 = 0
(x - 9)(x + 8) = 0
Find the possible values of Bea's age
x - 9 = 0
x = 9 That value works. She can be plus 9 years old.
x + 8 = 0
x = - 8. There's no way she can be - 8 years old
So Bea is 9.
9 <<<<<< Answer
Answer:
Incorrect.
Step-by-step explanation:
1 toss could not change the frequency by such a large margin 0.47 ---> 0.55.
The number of heads obtained in 30 tosses = 30 * 0.47 = 14.
So if the next toss came up heads the relative frequency of heads would be
15/31 = 0.48.
<span>0.4x + 6.1 = 0
0.4x = - 6.1
x = - 6.1 / 0.4
x = - 15.25</span>
