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Lemur [1.5K]
3 years ago
12

Structural formula for alkene with double bond st carbon 2 that shows no trans -cis isomerism C6H12​

Chemistry
1 answer:
svetlana [45]3 years ago
5 0

Answer:

Explanation:

Read up on this:

https://chem.libretexts.org/Bookshelves/Introductory_Chemistry/Book%3A_The_Basics_of_GOB_Chemistry_(Ball_et_al.)/13%3A_Unsaturated_and_Aromatic_Hydrocarbons/13.02%3A_Cis-Trans_Isomers_(Geometric_Isomers)

I think the answer is going to structure of 2-methyl-2-pentene.

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if a 500.0-g block of metal absorbs 5,016J of heat when its temperature changes from 20.00 Celcius, what is the specific heat?
ZanzabumX [31]
Correction: The temperature change is from 20 °C to 30 °C.

Answer:
               Cp  =  1.0032 J.g⁻¹.°C⁻¹

Solution:

The equation used for this problem is as follow,

                                                  Q  =  m Cp ΔT   ----- (1)

Where;
            Q  =  Heat  =  5016 J

            m  =  mass  =  500 g

            Cp  =  Specific Heat Capacity  =  ??

            ΔT  =  Change in Temperature  =  30 °C  -  20 °C  =  10 °C

Solving eq. 1 for Cp,

                                 Cp  =  Q / m ΔT

Putting values,
                                 Cp  =  5016 J / (500 g × 10 °C)

                                 Cp  =  1.0032 J.g⁻¹.°C⁻¹
4 0
3 years ago
Calculate the molarity when 135 g of KCl is dissolved to make a 2.50 L solution. Round to two significant digits.
inysia [295]
<h2>0.72 mol/L</h2>

Explanation:

       \textrm{Molarity of a solution}=\frac{\textrm{Number of moles of solvent}}{\textrm{Volume of solution in Liters}}

       We are given a 2.50L solution which contains 135g of KCl.

       To calculate number of moles of KCl present, we need to find it's molar mass from charts. Molar Mass of KCl is known to be 74.55\frac{g}{Mol}.

       Number of moles of KCl present = \frac{\textrm{Given weight}}{\textrm{Molar Mass}}\textrm{ = }\frac{135g}{74.55\frac{g}{Mol}}\textrm{ = }1.81087mol

       Molarity = \frac{1.81087mol}{2.50L}=0.7243\frac{mol}{L}

∴ Molarity of given KCl solution = 0.72\frac{mol}{L}

7 0
3 years ago
If a student made a 2.5 solution using 1.5 moles of sucrose how many liters of water were used?
saul85 [17]

Answer:

1 mole.

Explanation:

Hello there!

2.5-1.5=1

Subtract the sucrose moles from the total moles, and there you are!

:)

3 0
3 years ago
if you mixed 72.9g hydrochloric acid(aq) with 150g silver acetate(aq), what would be the limiting reagent?​
horsena [70]

Answer:

                      Silver Acetate would be the Limiting Reagent.

Explanation:

                    The balance chemical equation for the given double displacement reaction is as;

                            HCl + AgC₂H₃O₂ → AgCl + HC₂H₃O₂

Step 1: <u>Calculate Moles of Starting Materials:</u>

Moles of HCl:

                      Moles  =  Mass / M.Mass

                      Moles  =  72.9 g / 36.46

                      Moles =  1.99 moles

Moles of AgC₂H₃O₂:

                      Moles  =  150 g / 166.91 g/mol

                      Moles  =  0.898 moles

Step 2: <u>Find out Limiting reagent as:</u>

According to balance chemical equation.

              1 mole of HCl reacts with  =  1 mole of AgC₂H₃O₂

So,

         1.99 moles of HCl will react with  =  X moles of AgC₂H₃O₂

Solving for X,

                     X =  1.99 mol × 1 mol / 1 mol

                     X =  1.99 mol of AgC₂H₃O₂

Hence, to completely consume 1.99 moles of Hydrochloric acid we will require 1.99 moles of Silver Acetate, But, we are provided with only 0.898 moles of Silver Acetate. This means Silver Acetate will consume first in the reaction therefore, it is the LIMITING REAGENT.

8 0
3 years ago
Consider the reaction below. C2H4(g) + H2(g) to C2H6(g) Which change would likely cause the greatest increase in the rate of the
algol [13]
D. Increase temperature and increase pressure
4 0
3 years ago
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