All categories

3 years ago

Which type of radioactive emission has a positive charge and weak penetrating power?

Chemistry

1 answer:

vladimir2022 [97]3 years ago

3 0

1. The Alpha particle is a helium nucleus, is positively charged & would barely penetrate a piece of paper.<span />

You might be interested in

What of the following is NOT a common property of metals?

Yuri [45]

Answer:

have luster i think i dont know

Explanation:i need points

5 0

3 years ago

Does anyone know how to do this ??

lord [1]

Answer:

Look at your periodic table

Explanation:

It tells you everything like Potasium 1 and 1 ox and 1 hydrogen

7 0

3 years ago

Under certain conditions, the substance ammonium chloride can be broken down to form ammonia and hydrogen chloride. If 29.4 gram

lina2011 [118]

Answer: 20.0 g of hydrogen chloride must simultaneously be formed

Explanation:

The balanced chemical reaction is :

$NH_4Cl\rightarrow NH_3+HCl$

According to the law of conservation of mass, mass can neither be created nor be destroyed. The mass on reactant side must be equal to the mass on product side.

Thus mass of reactants = mass of products

Given : mass of ammonium chloride = mass of reactants = 29.4 g

mass of ammonia = 9.4 g

mass of products = mass of ammonia + mass of hydrogen chloride

9.4 g +mass of hydrogen chloride = 29.4 g

mass of hydrogen chloride = 20.0 g

5 0

3 years ago

Is a glass window good reflector of heat??

Inessa05 [86]

Answer:

Yes, Is a glass window good reflector of heat.

4 0

3 years ago

Read 2 more answers

2. Matt went to his friend’s party. He ate a big meal and drank a keg of beer. He felt heartburn after the meal and took Tums to

evablogger [386]

Answer:

390.85mL

Explanation:

Step 1:

Data obtained from the question.

Initial pressure (P1) = 780 torr

Initial volume (V1) = 400mL

Initial temperature (T1) = 40°C = 40°C + 273 = 313K

Final temperature (T2) = 25°C = 25°C + 273 = 298K

Final pressure (P2) = 1 atm = 760torr

Final volume (V2) =?

Step 2:

Determination of the final volume i.e the volume of the gas outside Matt's body.

The volume of the gas outside Matt's body can be obtained by using the general gas equation as shown below:

P1V1/T1 = P2V2/T2

780 x 400/313 = 760 x V2 /298

Cross multiply to express in linear form

313 x 760 x V2 = 780 x 400 x 298

Divide both side by 313 x 760

V2 = (780 x 400 x 298) /(313 x 760)

V2 = 390.85mL

Therefore, the volume of the gas outside Matt's body is 390.85mL

3 0

3 years ago