Answer:
dipole-dipole interactions.
Explanation:
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<span>Answer:
Zn(2+) + 2e(-) -------> Zn
1 mole of Zn is deposited by 2F of electricity ...
so 48.9 mole of Zn will be deposited by 48.9 X 2F = 97.8 F of electricity...
as 1F = 96500 C
so 97.8 F = 97.8 X 96500 = 9437700 C of electricity...</span>
See the image below.
An excited electron is in a <em>high-energy state</em>.
When it drops to the lower-level ground state, it must get rid of this excess energy by <em>emitting it</em> as a quantum of light.
