The three missing lengths are the left hypotenuse, x, the middle altitude, y, and the right hypotenuse, z.
9/y = y/16
y^2 = 9 * 16
y^2 = 144
y = 12
9^2 + 12^2 = x^2
x^2 = 225
x = 15
12^2 + 16^2 = z^2
z^2 = 400
z = 20
From left to right, the sides measure 15, 12, and 20 units.
3/6 because there are six sides to a dice.
EDIT: Picture
33) When adding matrices, just add the numbers that are in the same spot. In this problem we are given A and C, and we are asked to find B if A + B = C
So B = C - A
![\left[\begin{array}{ccc}2&-1&-3\\1&4&-2\\\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%26-1%26-3%5C%5C1%264%26-2%5C%5C%5Cend%7Barray%7D%5Cright%5D)
-
![\left[\begin{array}{ccc}4&9&-2\\-3&5&7\\\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%269%26-2%5C%5C-3%265%267%5C%5C%5Cend%7Barray%7D%5Cright%5D%20)
=
![\left[\begin{array}{ccc}-2&-10&-1\\4&-1&-9\\\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%26-10%26-1%5C%5C4%26-1%26-9%5C%5C%5Cend%7Barray%7D%5Cright%5D%20)
34) When multiplying matrices, the number of columns in the first matrix needs to be the same as the number of rows in the second matrix. Then the outcome will have the same number of rows as the first matrix and same number of columns as the second matrix. In this case, the result will be a 2x2.
Step 1: Substitute the value of x into the equation
x= 3-3/2y
-3x+5y=10
Step 2: Solve the equation
-3(3-3/2y)+5y=10
Step 3: Substitute the value of y into the equation
Y=2
Step 4: Solve the equation
X=3-3/2×2 = X=0
Answer: (0,2)