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2 years ago

HELP PLEASE

Mathematics

1 answer:

jok3333 [9.3K]2 years ago

3 0

Answer:

Step-by-step explanation:

I mean I believe its b it looks like theres three

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The unit circle edgenunity answers

lawyer [7]

Answer:

go to The unit circle edgenunity on quizlet it gives you the answers

Step-by-step explanation:

can I get brainliest

7 0

3 years ago

Suppose a triangle has sides a, b, and c, and the angle opposite the side of length b is obtuse. What must be true?

anyanavicka [17]

Answer: D. $a^2 + b^2 < c^2$

Step-by-step explanation:

In the given figure, we have an obtuse triangle which has sides a, b, and c, and the angle opposite the side of length b is obtuse.

∵ In a triangle, the side opposite to the largest angle is largest.

Thus, the largest side in then given obtuse triangle= c

The Pythagorean inequalities theorem says that If a triangle is obtuse than the square of the largest side is greater than the sum of square of other two sides.

Therefore, we have

$a^2 + b^2 < c^2$

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2 years ago

Write an expression that is equivalent to - 0.5(14a - 22) .

PSYCHO15rus [73]

$\textsf{Hey \: there}$

<h2>QUESTION</h2>

$\mathsf{-0.5(14a - 22)}$

<h2>FIRST YOU HAVE TO DISTRIBUTE:</h2>

$\mathsf{(-0.5)(14a) + (-0.5)( -22)}$

<h2>SOLVING FOR OUR ANSWER</h2>

$\mathsf{(0.5)(14a) = - 7a} \\ \\ \mathsf{( - 0.5)( - 22) = 11}$

<h2 /><h2>NEW EQUATION/THE ANSWER YOU WERE LOOKING FOR </h2>

$\boxed{ \bf{your \: answer:} \boxed{ \huge \textsf{ \bf- 7a + 11}}} \checkmark$

<h2>GOOD LUCK ON YOUR ASSIGNMENT AND ENJOY YOUR DAY!</h2>

$\dfrac{\frak{LoveYourselfFirst}}{:)}$

<h2>SIDE NOTE: THE DISTRIBUTIVE FORMULA IS</h2>

$\text{a(b + c)} \\ \text{a(b) + a(c)} \\ \text{a(b) = ab} \\ \text{a(c) = ac} \\ \text{ \underline{ = ab + ac}}$

5 0

2 years ago

Read 2 more answers

Answer with A B C D or #. Correct answer gets brainlest.

gladu [14]

Answer:

256

Step-by-step explanation:

4×4=16

16×4=64

64×4=256

8 0

3 years ago

Write the following cubes in expanded form .

bulgar [2K]

Hope that this helps

4 0

2 years ago