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pashok25 [27]
3 years ago
8

8.3 is equal to tenths hundredths​

Mathematics
2 answers:
irakobra [83]3 years ago
6 0

Answer:  

83 Tenths  

830 hundreths  

Step-by-step explanation:  

8.30=8.3 Remove the points and they will give you how many tenths or hundreths

(hope this helps can i plz have brainlist :D hehe)

DochEvi [55]3 years ago
3 0

Answer:

8.3 tenths place is 3

8.3 hundredths place is 0

Why?

Because the first digit right of the decimal point will always be considered the tenths place, the second digit of the right of the decimal point is going to be the hundredths place, in this case it is 0 since there is no value of the hundredths place so you simply consider it 0. The tenths place is given since it is the first digit right of the decimal point, which is 3.

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a sea turtles was recorded to swim at a speed of 6 miles in 30 minutes. at this same rate, how far would the turtle travel in 90
Ede4ka [16]

Answer:

The turtle will go 18 miles in 90 minutes.

Step-by-step explanation:

6 divided by 30 = 0.2

0.2 x 90 = 18

18 miles

8 0
3 years ago
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erma4kov [3.2K]

Answer:

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4 0
3 years ago
The monthly demand equation for an electric utility company is estimated to be p equals 59 minus (10 Superscript negative 5 Base
mestny [16]

Answer:

a) The price that maximizes profit is p =$43.

b) The utility shouldn't pass all this increase on the consumers because this would mean a decrease in the profits. They should pass only $7 to consumers price.

Step-by-step explanation:

We have an electric utility company which has a demand function defined by:

p=59-10^{-5}x

where p is the price and x is the the energy in thousands of kWh.

The cost of the company is defined as:

C(x)=3\cdot 10^6+27x

We have to calculate the price that maximizes the utility's profit R(x).

We can define the profit as:

R(x)=p\cdot x-C=(59-10^{-5}x)\cdot x-(3\cdot 10^6+27x)\\\\R(x)=-10^{-5}x^2+(59-27)x-3\cdot10^6\\\\R(x)=-10^{-5}x^2+32x-3\cdot10^6.

To maximize R, we have to derive it and equal to zero

\dfrac{dR}{dx}=0\\\\\\\dfrac{dR}{dx}=-2\cdot10^{-5}x+32=0\\\\\\x=(32/2)\cdot 10^5=16\cdot 10^5=1.6\cdot 10^6

The price that maximizes the profit is then:

p=59-10^{-5}x=59-10^{-5}(16\cdot 10^5)=59-16=43

b) When the unit cost rise from $27 to $41, the utility profit function changes.

We have to calculate the new price that maximizes profit, and then we will know if the rise in cost was transferred to price completely.

The new profit function is:

R(x)=p\cdot x-C=(59-10^{-5}x)\cdot x-(3\cdot 10^6+41x)\\\\R(x)=-10^{-5}x^2+(59-41)x-3\cdot10^6\\\\R(x)=-10^{-5}x^2+18x-3\cdot10^6

To maximize R, we have to derive it and equal to zero

\dfrac{dR}{dx}=0\\\\\\\dfrac{dR}{dx}=-2\cdot10^{-5}x+18=0\\\\\\x=(18/2)\cdot 10^5=9\cdot 10^5

We calculate the new price as:

p=59-10^{-5}x=59-10^{-5}(9\cdot 10^5)=59-9=50

The new price is $7 dollars above the previous maximizing price, so the rise in unit cost is only transferred 50% to the price.

The utility shouldn't pass all this increase on the consumers because this would mean a decrease in the profits. They should pass only $7 to consumers price.

4 0
3 years ago
Please answer carefully.
nadezda [96]

Answer:

BC = 21

Step-by-step explanation:

We know that AB + BC = AC

First we need to solve for x so using what we know lets set up the equation.

AB = 7x + 8

BC = 3x + 6

AC = 64

So (7x + 8) + (3x + 6) = 64

Combine like terms and solve.

10x + 14 = 64

10x = 50

x = 5

Now that we know that x = 5, to find the number for BC let's put that into the BC expression

3(5) + 6 = 21

There's your answer. BC = 21

Now if you really wanna make sure you can input the values we've found into the equation we first made.

AB + 21 = 64

7x + 8 + 21 = 64

7(5) + 8 +21 = 64

35 + 29 = 64

64 = 64

5 0
4 years ago
Joan waters her plants each day with gallons of water. With a new irrigation system in place, she uses gallons of water each day
vampirchik [111]

Answer:

172\frac{1}{2} gallons

Step-by-step explanation:

Considering she waters her plants with 25 1/2 gallons  i.e 51/2

and with the new system, she does it with 19 3/4 i.e 79/4

taking the difference:

\frac{51}{2} - \frac{70}{4} = \frac{23}{4} gallons per day

For 30 days:

30 x \frac{23}{4} = 172.5 or 172\frac{1}{2} gallons

8 0
3 years ago
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