Answer:
Step-by-step explanation:
Problem A
t(1) = 2(1) + 5
t(2) = 2*2 + 5 = 9
t(3) = 2*3 + 5 = 11
t(4) = 2*4 + 5 = 13
So this is the explicit result. Now try it recursively.
t_3 = t_2 + 2
t_3 = 9 + 2
t_3 = 11 which is just what it should do.
t_n = t_(n - 1) + 2
Problem B
t(1) = 3 * 1/2
t(1) = 3/2
t(2) = 3*(1/2)^2
t(2) = 3 * 1/4
t(2) = 3/4
t(3) = 3*(1/2)^3
t(3) = 3 * 1/8
t(3) = 3/8
t(4) = 3 (1/2)^4
t(4) = 3 (1/16)
t(4) = 3/16
So in general
t_n = t_n-1 * 1/2
For example t(5)
t_5 = t_4 * 1/2
t_5 = 3 /16 * 1/2 = 3/32
Multiply the top and bottom by (3√(7)+√(3)).
This will give you (9√(21)+9)/60.
Then take out a 3, giving you (3(3√(21)+3))/(3*20).
Finally, the 3s cancel out and leave you with (3√(21)+3)/20 as your answer.
ANSWER: (3√(21)+3)/20
Her total depth will be the sum of those numbers, and they seem to want it with a negative sign so we give it to them that way.
First answer.
Answer: 4/3 or 1 1/3 feet
Step-by-step explanation:
12 months make a year.
Since the shoreline is eroding at 1/3 foot per 3 months, for a year it will be:
1/3 × 12/3 = 4/3 or 1 1/3 feet
In simplest form the fraction 60/78 reduces to 10/13