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never [62]
3 years ago
11

Plz answer....,.......................

Mathematics
1 answer:
Aleksandr [31]3 years ago
3 0

Answer:

B and C

Step-by-step explanation:

Not A because the side lengths aren't multiples.

Not D because it would be congruent, unless it had different angles, but then similar shaps must have the same angles

Good luck <3

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3
prohojiy [21]

Answer:

30cm

Step-by-step explanation:

Divide the circumference by π, or 3.14 for an estimation.

29.9 so closest 30cm

6 0
3 years ago
Explain why the expression 9x^3+1/2x^2+3x^-1 is not a polynomial
Nastasia [14]

Answer:

The given expression can't be expressed in polynomial form. Hence, it is not a polynomial.

Step-by-step explanation:

P(x,n) is a polynomial of nth degree if it is of the form,

P(x,n) = a_{0} + a_{1}x + a_{2}x^{2} + a_{3}x^{3} + ......... +a_{n}x^{n}

where n is a finite positive integer and n ∈ N

and 'a_{i}'s are fixed but otherwise arbitrary constants ∀  i = 0(1)n .

Now, the given expression is,

9x^{3} + \frac {1}{2x^{2}} + 3x^{-1}

which  doesn't fit in the above form. Hence, it is not a polynomial.

4 0
4 years ago
What is the mode?<br><br> 0 7 7 7 0
posledela

Answer:

7

Step-by-step explanation:

7 is shown the most out of the 5 numbers

7 0
3 years ago
What is the area of this figure
N76 [4]

Answer:

153.86

Step-by-step explanation:

Divide the diameter by 2 to find the radius

14/2=7

A=3.14(7^{2})

A=3.14(49)

A=153.86

6 0
3 years ago
Read 2 more answers
The shadow of a flag pole is 28 ft long. the distance from the tip of the shadow to the top of the pole is 33 ft. how tall is th
JulsSmile [24]

Answer:

Step 1: Our output value is 15.

Step 2: We represent the unknown value with $x$.

Step 3: From step 1 above,$15=100\%$.

Step 4: Similarly, $x=60\%$.

Step 5: This results in a pair of simple equations:

$15=100\%(1)$.

$x=60\%(2)$.

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

$\frac{15}{x}=\frac{100\%}{60\%}$

Step 7: Again, the reciprocal of both sides gives

$\frac{x}{15}=\frac{60}{100}$

$\Rightarrow x=9$

Therefore, $60\%$ of $15$ is $9$Step 1: Our output value is 15.

Step 2: We represent the unknown value with $x$.

Step 3: From step 1 above,$15=100\%$.

Step 4: Similarly, $x=60\%$.

Step 5: This results in a pair of simple equations:

$15=100\%(1)$.

$x=60\%(2)$.

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

$\frac{15}{x}=\frac{100\%}{60\%}$

Step 7: Again, the reciprocal of both sides gives

$\frac{x}{15}=\frac{60}{100}$

$\Rightarrow x=9$

Therefore, $60\%$ of $15$ is $9$Step 1: Our output value is 15.

Step 2: We represent the unknown value with $x$.

Step 3: From step 1 above,$15=100\%$.

Step 4: Similarly, $x=60\%$.

Step 5: This results in a pair of simple equations:

$15=100\%(1)$.

$x=60\%(2)$.

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

$\frac{15}{x}=\frac{100\%}{60\%}$

Step 7: Again, the reciprocal of both sides gives

$\frac{x}{15}=\frac{60}{100}$

$\Rightarrow x=9$

Therefore, $60\%$ of $15$ is $9$Step 1: Our output value is 15.

Step 2: We represent the unknown value with $x$.

Step 3: From step 1 above,$15=100\%$.

Step 4: Similarly, $x=60\%$.

Step 5: This results in a pair of simple equations:

$15=100\%(1)$.

$x=60\%(2)$.

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

$\frac{15}{x}=\frac{100\%}{60\%}$

Step 7: Again, the reciprocal of both sides gives

$\frac{x}{15}=\frac{60}{100}$

$\Rightarrow x=9$

Therefore, $60\%$ of $15$ is $9$Step 1: Our output value is 15.

Step 2: We represent the unknown value with $x$.

Step 3: From step 1 above,$15=100\%$.

Step 4: Similarly, $x=60\%$.

Step 5: This results in a pair of simple equations:

$15=100\%(1)$.

$x=60\%(2)$.

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

$\frac{15}{x}=\frac{100\%}{60\%}$

Step 7: Again, the reciprocal of both sides gives

$\frac{x}{15}=\frac{60}{100}$

$\Rightarrow x=9$

Therefore, $60\%$ of $15$ is $9$Step 1: Our output value is 15.

Step 2: We represent the unknown value with $x$.

Step 3: From step 1 above,$15=100\%$.

Step 4: Similarly, $x=60\%$.

Step 5: This results in a pair of simple equations:

$15=100\%(1)$.

$x=60\%(2)$.

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

$\frac{15}{x}=\frac{100\%}{60\%}$

Step 7: Again, the reciprocal of both sides gives

$\frac{x}{15}=\frac{60}{100}$

$\Rightarrow x=9$

Therefore, $60\%$ of $15$ is $9$Step 1: Our output value is 15.

Step 2: We represent the unknown value with $x$.

Step 3: From step 1 above,$15=100\%$.

Step 4: Similarly, $x=60\%$.

Step 5: This results in a pair of simple equations:

$15=100\%(1)$.

$x=60\%(2)$.

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

$\frac{15}{x}=\frac{100\%}{60\%}$

Step 7: Again, the reciprocal of both sides gives

$\frac{x}{15}=\frac{60}{100}$

$\Rightarrow x=9$

Therefore, $60\%$ of $15$ is $9$Step 1: Our output value is 15.

Step 2: We represent the unknown value with $x$.

Step 3: From step 1 above,$15=100\%$.

Step 4: Similarly, $x=60\%$.

Step 5: This results in a pair of simple equations:

$15=100\%(1)$.

$x=60\%(2)$.

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

$\frac{15}{x}=\frac{100\%}{60\%}$

Step 7: Again, the reciprocal of both sides gives

$\frac{x}{15}=\frac{60}{100}$

$\Rightarrow x=9$

Therefore, $60\%$ of $15$ is $9$

Step-by-step explanation:

8 0
3 years ago
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