<span>The strong bonds give graphite high boiling and melting points, while the weak bonds make graphite soft and flexible.</span>
Answer:
If 51.8 of Pb is reacting, it will require 4.00 g of O2
If 51.8 g of PbO is formed, it will require 3.47 g of O2.
Explanation:
Equation of the reaction:
2 Pb + O2 → 2 PbO
From the equation of reaction, 2 moles of lead metal, Pb, reacts with 1 mole of oxygen gas, O2, to produce 2 moles of lead (ii) oxide, PbO
Molar mass of Pb = 207 g
Molar mass of O2 = 32 g
Molar mass of PbO = 207 + 32 = 239 g
Therefore 2 × 207 g of Pb reacts with 32 g of O2 to produce 2 × 239 g of PbO
= 414 g of Pb reacts with 32 g of O2 to produce 478 g of PbO
Therefore, formation of 51.8 g of PbO will require (32/478) × 51.8 of O2 = 3.47 g of O2.
If 51.8 of Pb is reacting, it will require (32/414) × 51.8 g of O2 = 4.00 g of O2
The order of the solutions from lowest to highest concentration : A, B, C
<h3>Further explanation</h3>
Given
the following solutions
Required
order of increasing concentration
Solution
Molarity shows the number of moles of solute in every 1 liter of solution.
Solution A : 0.5 moles : 2 L solution = 0.25 M
Solution B : 1 moles : 3 L solution = 0.33 M
Solution C : 1.5 moles : 4 L solution = 0.375 M
