Answer:
They are already matched for you. It goes
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in the order of the questions.
The average rate of a reaction is a good approximation of an instantaneous rate when the concentration is measured during relatively brief time intervals.
At any point during such a little period, the average rate will be extremely near to the instantaneous rate. The average rate will differ from the instantaneous rates inside the period more when time intervals are longer.
The concentration change during a chosen time period is the average rate. When you take the measurements makes a difference.
The rate at a specific moment is known as the instantaneous rate. Finding the slope of the tangent to the concentration vs. time curve at that point yields the answer.
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Answer:
The pH of a 0.10 Maqueous Ba(OH)2 solution at 25°C is 13.30
Explanation:
The balanced equation is Ba(OH)2(s)→Ba2++2OH−
This indicates that the concentration is 0.2 M
We will find H+ ion concentration
As we know that
[H+][OH−]=1.0×10−14M
Given -
[OH−]=2.0×10−1M
Putting value of [OH-] in above equation we get -
[H+]=5.0×10−14M
pH=−log10[H+]
pH=−log10[5.0×10−14] = 13.30.
Answer:
Hb would be 78.4% saturated.
Explanation:
This problem can be solved by using simple unitary method.
At 100 mm Hg pressure of oxygen, Hb is saturated by 98%
So, at 1 mm Hg pressure of oxygen, Hb is saturated by 
%
Hence, at 80 mm Hg pressure of oxygen, Hb is saturated by 
% or 78.4%
Therefore, at 80 mm Hg pressure of oxygen in the lungs, Hb would be 78.4% saturated.
The reaction between iron(II) oxide and carbon monoxide produces iron and carbon dioxide. 3.00 moles of iron can be obtained when 3.00 mol FeO reacts with an excess of CO
<u>Explanation:</u>
During the chemical reaction, products are formed on the basis of the number of moles of reactants available, especially limiting factors. The moles from those reactants is then adapted to balanced chemical reaction factors to form products.
The balanced chemical equation is
Mole ratio of FeO : Fe is 1:1
That is mole of FeO produces 1 mole of Fe
Given, 
So,
= 
= 3.00mol Fe is obtained.
