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Juli2301 [7.4K]
3 years ago
14

Buddhism was first brought to China via the

Chemistry
2 answers:
Verdich [7]3 years ago
7 0

Answer:

The Silk Road

Explanation:

Buddhism entered CHINA via the Silk Road beginning in the 1st and 2nd centuries they had.

Firdavs [7]3 years ago
3 0

Answer:

In the 1800s era

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What charge would Balloon #2 have? How did you determine this?
tigry1 [53]

Answer:I belive it would be attracted seeing as how there are more magmatic charges on that side of no 2 and how there are more positive charges on the middle side of ballon no1.

Explanation:

4 0
3 years ago
PLEASE HELP 20 points
777dan777 [17]

  n = 1.5atm (15L) / .0821 (280k) = .98 mol NaCl

  NaCl = 22.99g Na + 35.45g Cl = 58.44g NaCl

  58.44g NaCl x .98 mol NaCl = 57.27g NaCl

Explanation:

hope you get it right :)

4 0
2 years ago
When an atom of calcium (Ca) forms an ion by losing two electrons, what is the ion’s type and charge?
Svetllana [295]

Answer: it would be cation, 2+

Explanation: electrons are negatively charged by 1. So if you get rid of 2 electrons it would be positive and cation is used to represent positive ions.

8 0
3 years ago
Read 2 more answers
The cell potential of a redox reaction occurring in an electrochemical cell under any set of temperature and concentration condi
avanturin [10]

Answer : The actual cell potential of the cell is 0.47 V

Explanation:

Reaction quotient (Q) : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.

The given redox reaction is :

Ni^{2+}(aq)+Zn(s)\rightarrow Ni(s)+Zn^{2+}(aq)

The balanced two-half reactions will be,

Oxidation half reaction : Zn\rightarrow Zn^{2+}+2e^-

Reduction half reaction : Ni^{2+}+2e^-\rightarrow Ni

The expression for reaction quotient will be :

Q=\frac{[Zn^{2+}]}{[Ni^{2+}]}

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

Q=\frac{(0.0141)}{(0.00104)}=13.6

The value of the reaction quotient, Q, for the cell is, 13.6

Now we have to calculate the actual cell potential of the cell.

Using Nernst equation :

E_{cell}=E^o_{cell}-\frac{RT}{nF}\ln Q

where,

F = Faraday constant = 96500 C

R = gas constant = 8.314 J/mol.K

T = room temperature = 316 K

n = number of electrons in oxidation-reduction reaction = 2 mole

E^o_{cell} = standard electrode potential of the cell = 0.51 V

E_{cell} = actual cell potential of the cell = ?

Q = reaction quotient = 13.6

Now put all the given values in the above equation, we get:

E_{cell}=0.51-\frac{(8.314)\times (316)}{2\times 96500}\ln (13.6)

E_{cell}=0.47V

Therefore, the actual cell potential of the cell is 0.47 V

4 0
3 years ago
X-x/4-1/3=2+x/4 please answer me ​
Karo-lina-s [1.5K]

Answer:

x= 14/3 = 4.667

Explanation:

X - X/4 - 1/3 = 2 + X/4

7 0
3 years ago
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