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Amanda [17]
3 years ago
11

How many moles of oxygen are needed to react with 87 grams of aluminum

Chemistry
1 answer:
labwork [276]3 years ago
5 0

Answer:

2.4 moles of oxygen are needed to react with 87 g of aluminium.

Explanation:

Chemical equation:

4Al(s)  + 3O₂(l)   → 2AlO₃(s)

Given data:

Mass of aluminium = 87 g

Moles of oxygen needed = ?

Solution:

Moles of aluminium:

Number of moles of aluminium= Mass/ molar mass

Number of moles of aluminium= 87 g/ 27 g/mol

Number of moles of aluminium= 3.2 mol

Now we will compare the moles of aluminium with oxygen.

                              Al         :         O₂

                               4          :         3

                               3.2       :         3/4×3.2 = 2.4 mol

2.4 moles of oxygen are needed to react with 87 g of aluminium.

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Reversible reaction and examples on them
Tomtit [17]

Answer:

Here are three examples  

Explanation:

In a reversible reaction, the conversions of reactants to products and of products to reactants occur at the same time.

Example 1

The reaction of hydrogen and iodine to from hydrogen iodide.  

H₂ + I₂ ⇌ 2HI

Example 2

The dissociation of carbonic acid in water to form hydronium and hydrogen carbonate ions

H₂CO₃ + H₂O ⇌ H₃O⁺ + HCO₃⁻

Example 3

The dissociation of dinitrogen tetroxide to nitrogen dioxide.

N₂O₄ ⇌ 2NO₂

4 0
3 years ago
What conclusion can be draw about the heat of fusion of water from the heating curve? A) The potential energy of fusion represen
zysi [14]
The answer would be c.

6 0
3 years ago
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The boiling process is considered to be____
Dmitry_Shevchenko [17]

your answer is <u>D</u><u>.</u><u> </u>physical change, because a new substance is not formed.

5 0
3 years ago
The bulb lights up in the circuit. Only two rods are conductors of electricity. Which one of the rods, X, Y or Z is definitely a
meriva

Answer: Rod X.

Explanation:

Ok, the electricity starts in the top left part. First, it must travel in the X rod, then it keeps traveling until it reaches the parallel path, and it can go to the Z rod, to the Y rod, or to both of them, and then it reaches the bulb (the circle with a X inside of it).

We know that two rods are conductors of electricity.

Now, suppose the case where rods Z and Y are the ones that conduct electricity, this means that X does not conduct electricity, then when the current reaches to X it stops (because X does not conduct) then the electricity never reaches the rods Z and Y, and then the electricity never reaches the bulb, but we know that the bulb lights up, so we must have that X is one of the conducting rods.

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4 0
3 years ago
When 250 ml of water is added to 35 ml of 0.2 M HCl
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Assuming that you’re looking for the concentration of water in the solution, then it would be 0.028 M.

You would have to use the formula:
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v = volume

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C1 = (0.2 M x 35 mL) / 250 mL

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Therefore, there is 0.028 M of water added to 35mL of 0.2M HCl
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3 years ago
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