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3 years ago

How many types of alkanol do we have

Chemistry

1 answer:

oksano4ka [1.4K]3 years ago

6 0

I think you mean alcohol ? if so there are a few basic types including ethanol

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An orbital is the space occupied by a pair of electrons.<br> true or false??

Anvisha [2.4K]

Answer:

True

Explanation:

An orbital is is the space occupied by a pair of electrons. The maximum number of electrons in an orbital is 2.

The maximum number of electrons in in the orbitals are two.

For s-sublevel with one orbital we have two electrons

p-sublevel with three orbitals we have six electrons

d - sublevel with five orbitals we have ten electrons

f - sublevel with seven orbitals we have fourteen electrons

Each orbital can take a maximum of two electrons.

7 0

3 years ago

Need some help please?

VladimirAG [237]

26. B. 28. B. 20. A.

4 0

2 years ago

How much energy (in Joules) is needed to increase the temperature of 25 grams of glass by 5.0C. Aluminum Iron Glass Copper Water

vitfil [10]

Answer:

25 grams of glass by 5.oc aluminium iron glass copper water

4 0

3 years ago

Lionel has a hot plate, a thermometer, a container of water, a spoon, and a small hammer. Using these tools,

DIA [1.3K]

Answer:

atomic structure

Explanation:

Its pretty obvious. Nothing here can test atomic structure. You can test melting point, with a hot plate. You can test the ability to dissolve something with the container of water. You can test brittleness with the hammer.

6 0

3 years ago

Read 2 more answers

A sample of propane (C3H8) has a mass of 0. 47 g. The sample is burned in a bomb calorimeter that has a mass of 1. 350 kg and a

Nady [450]

The amount of heat released by the sample has been 22.54 kJ. Thus, option C is correct.

The specific heat has been defined as the amount of heat required to raise the temperature of 1 gram of substance by 1 degree Celsius.

The specific heat has been expressed as:

$q=mc\Delta T$

<h3 /><h3>Computation for the heat absorbed</h3>

The iron and calorimeter are in side the closed system. Thus, the energy released by the sample, has been equivalent to the energy absorbed by the calorimeter.

$q_{released}=q_{absorbed}\\
q_{released}=m_{calorimeter}\;c_{calorimeter}\;\Delta T$

The given mass of calorimeter has been, $m_{calorimeter}=1350\;\rm g$

The specific heat of the calorimeter has been, $c_{calorimeter}=5.82\;\rm J/g^\circ C$

The change in temperature of the calorimeter has been, $\Delta T=2.87^\circ \rm C$

Substituting the values for heat released:

$q_{released}= 1350\;\text g\;\times\;5.82\;\text J/\text g^\circ \text C\;\times\;2.87^\circ \text C\\
q_{released}=22,549.5\;\text J\\
q_{released}}=22.54\;\rm kJ$

The amount of heat released by the sample has been 22.54 kJ. Thus, option C is correct.

Learn more about specific heat, here:

brainly.com/question/2094845

6 0

2 years ago