Answer:
a) d²y/dx² = ½ x + y − ½
b) Relative minimum
Step-by-step explanation:
a) Take the derivative with respect to x.
dy/dx = ½ x + y − 1
d²y/dx² = ½ + dy/dx
d²y/dx² = ½ + (½ x + y − 1)
d²y/dx² = ½ x + y − ½
b) At (0, 1), the first and second derivatives are:
dy/dx = ½ (0) + (1) − 1
dy/dx = 0
d²y/dx² = ½ (0) + (1) − ½
d²y/dx² = ½
The first derivative is 0, and the second derivative is positive (concave up). Therefore, the point is a relative minimum.
<u>Answer:</u>
The number of tickets bought is 1000 adults tickets and 700 children were present
<u>Explanation:</u>
Let the number of children and adults present in the circus be x and y respectively
According to question,
Then, x + y = 1700 ……………..equation (1)
And, cost of ticket to circus for children and adult be 19, 42 respectively
Total cost of ticket;
for adults = 42y; for children = 19x
19x + 42y = 55300 …………………equation (2)
Multiplying equation (1) by 19
19x + 19y = 32300 ……………… eqn (3)
Subtracting equation 1 and 3, we get
23y = 23000
y = 1000
putting this value in eq (1), we get x = 700
Therefore, 1000 adults and 700 children were present
.
Let x = the length of the triangle's hypotenuse
using proportions, this is what the equation looks like:
cross multiply to get:
divide both sides by 45 to get
x=12
Answer
1 + 32 + 243 + 1024 + .. + n5
Step-by-step explanation:
Answer with Step-by-step explanation:
We are given that
The probability that an American CEO can transact business in foreign language=0.20
The probability than an American CEO can not transact business in foreign language=
Total number of American CEOs chosen=12
a. The probability that none can transact business in a foreign language=
Using binomial theorem 
The probability that none can transact business in a foreign language=
b.The probability that at least two can transact business in a foreign language=
c.The probability that all 12 can transact business in a foreign language=
The probability that all 12 can transact business in a foreign language=