<h3><u>Answer;</u></h3>
Energy
<h3><u>Explanation;</u></h3>
- A wave is a transmission of disturbance from one point to another. All waves involve transmission of energy from one point called the source to another point.
- <em><u>Waves describes various ways in which energy can be transferred from a point source.</u></em>
- <em><u>In electromagnetic waves</u></em><em>, for instance, </em><em><u>energy transmission occurs as a result of vibrations of electric and magnetic fields</u></em><u>.</u>
- <u><em>In mechanical waves energy transmission is as a result of vibration of particles in the medium used</em></u>. For example in sound waves, energy is transferred through vibration of particles of air or particles of a solid or medium through which sound travels through.
Answer:
step bro was stuck on the elevator
Explanation:
Answer:
The angular acceleration is ![\alpha = 3.235 \ rad/s ^2](https://tex.z-dn.net/?f=%5Calpha%20%20%3D%203.235%20%5C%20rad%2Fs%20%5E2)
Explanation:
From the question we are told that
The moment of inertia is ![I = 0.034\ kg \cdot m^2](https://tex.z-dn.net/?f=I%20%20%3D%20%200.034%5C%20kg%20%5Ccdot%20m%5E2)
The net torque is ![\tau = 0.11\ N \cdot m](https://tex.z-dn.net/?f=%5Ctau%20%20%3D%20%200.11%5C%20N%20%5Ccdot%20m)
Generally the net torque is mathematically represented as
![\tau = I * \alpha](https://tex.z-dn.net/?f=%5Ctau%20%3D%20%20I%20%20%2A%20%20%5Calpha)
Where
is the angular acceleration so
![\alpha = \frac{\tau }{I}](https://tex.z-dn.net/?f=%5Calpha%20%20%3D%20%20%5Cfrac%7B%5Ctau%20%7D%7BI%7D)
substituting values
![\alpha = \frac{0.1 1}{ 0.034}](https://tex.z-dn.net/?f=%5Calpha%20%20%3D%20%20%5Cfrac%7B0.1%201%7D%7B%200.034%7D)
![\alpha = 3.235 \ rad/s ^2](https://tex.z-dn.net/?f=%5Calpha%20%20%3D%203.235%20%5C%20rad%2Fs%20%5E2)
Answer:
ms⁻¹
Explanation:
= diameter of merry-go-round = 4 m
= radius of merry-go-round =
=
= 2 m
= moment of inertia = 500 kgm²
= angular velocity of merry-go-round before ryan jumps = 2.0 rad/s
= angular velocity of merry-go-round after ryan jumps = 0 rad/s
= velocity of ryan before jumping onto the merry-go-round
= mass of ryan = 70 kg
Using conservation of angular momentum
![Iw_{i} - m v r = (I + mr^{2})w_{f}](https://tex.z-dn.net/?f=Iw_%7Bi%7D%20-%20m%20v%20r%20%3D%20%28I%20%2B%20mr%5E%7B2%7D%29w_%7Bf%7D)
![(500)(2.0) - (70) v (2) = (I + mr^{2})(0)](https://tex.z-dn.net/?f=%28500%29%282.0%29%20-%20%2870%29%20v%20%282%29%20%3D%20%28I%20%2B%20mr%5E%7B2%7D%29%280%29)
![1000 = 140 v](https://tex.z-dn.net/?f=1000%20%3D%20140%20v)
ms⁻¹
Answer:
![t=6.96s](https://tex.z-dn.net/?f=t%3D6.96s)
Explanation:
From this exercise, our knowable variables are <u>hight and initial velocity </u>
![v_{oy}=96ft/s](https://tex.z-dn.net/?f=v_%7Boy%7D%3D96ft%2Fs)
![y_{o}=112ft](https://tex.z-dn.net/?f=y_%7Bo%7D%3D112ft)
To find how much time does the <u>ball strike the ground</u>, we need to know that the final position of the ball is y=0ft
![y=y_{o}+v_{oy}t+\frac{1}{2}gt^{2}](https://tex.z-dn.net/?f=y%3Dy_%7Bo%7D%2Bv_%7Boy%7Dt%2B%5Cfrac%7B1%7D%7B2%7Dgt%5E%7B2%7D)
![0=112ft+(96ft/s)t-\frac{1}{2}(32.2ft/s^{2})t^{2}](https://tex.z-dn.net/?f=0%3D112ft%2B%2896ft%2Fs%29t-%5Cfrac%7B1%7D%7B2%7D%2832.2ft%2Fs%5E%7B2%7D%29t%5E%7B2%7D)
Solving for t using quadratic formula
![t=\frac{-b±\sqrt{b^{2}-4ac } }{2a}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B-b%C2%B1%5Csqrt%7Bb%5E%7B2%7D-4ac%20%7D%20%7D%7B2a%7D)
![a=-\frac{1}{2} (32.2)\\b=96\\c=112](https://tex.z-dn.net/?f=a%3D-%5Cfrac%7B1%7D%7B2%7D%20%2832.2%29%5C%5Cb%3D96%5C%5Cc%3D112)
or ![t=6.96s](https://tex.z-dn.net/?f=t%3D6.96s)
<u><em>Since time can't be negative the answer is t=6.96s</em></u>