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viva [34]
3 years ago
7

A speaker that emits sound is located at the origin of a coordinate system. Two microphones are located on the x-axis, with micr

ophone 1 at the x = 3.0 meter mark and microphone 2 at the x = 5.0 meter mark. If the speed of sound is 343 m/s, how much longer does it take a sound emitted by the speaker to reach microphone 2 than microphone 1?
Physics
1 answer:
Taya2010 [7]3 years ago
5 0

Answer:

0.00583 seconds

Explanation:

Distance from mic 1 to origin = 3 m

Distance from mic 2 to origin = 5 m

Speed of sound = 343 m/s

Time taken by mic 1

t_1=\frac{\text{Distance from mic 1 to origin}}{\text{Speed of sound}}\\\Rightarrow t_1=\frac{3}{343}=0.008746\ s

t_2=\frac{\text{Distance from mic 2 to origin}}{\text{Speed of sound}}\\\Rightarrow t_2=\frac{5}{343}=0.014577\ s

Time difference = t₂ - t₁ = 0.14577-0.008746 = 0.00583 s

∴ Difference in time taken by the speaker is 0.00583 s

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1. An express train, traveling at 36 m/s, is accidentally sidetracked onto a local train track. The express engineer spots a loc
Colt1911 [192]

Answer:

(i) 12 seconds

(ii) 216 meters from the initial position

(iii) 132 meters from the initial position

(iv) No

Explanation:

Speed of express train =36 m/s

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The initial distance between the local train and passenger train =100 m.

Due to the application of breaks, the express train slows at the rare of 3.0 m/s^2.

So, the acceleration of the express train, a=-3 m/s^2.

(i) Let t be the time the express train takes to stop.

From the equation of motion,

v=u+at

where, v: final velocity, u: initial velocity, a: constant acceleration, t: time taken to change the speed from u to v.

In this case, v=0, u=36 m/s, a=-3 m/s^2

So, 0=36+(-3)t

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(ii) To compute the distance traveled, s, till the express train stops, using

v^2=u^2+2as

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(iii) The local train is moving at a speed of 11 m/s

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(iv) Let 0 be the reference position which is the initial position of the express train.

So, at the initial time, the position of the local train is at 100m.

After 12 seconds:

The position of the express train is at 216 m [using part (ii)]

and the position of the local train is at 100+132=232m  [using part (iii)].

So, the local train is still ahead of the express train, hence the trains didn't collide.

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Answer:

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