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viva [34]
3 years ago
7

A speaker that emits sound is located at the origin of a coordinate system. Two microphones are located on the x-axis, with micr

ophone 1 at the x = 3.0 meter mark and microphone 2 at the x = 5.0 meter mark. If the speed of sound is 343 m/s, how much longer does it take a sound emitted by the speaker to reach microphone 2 than microphone 1?
Physics
1 answer:
Taya2010 [7]3 years ago
5 0

Answer:

0.00583 seconds

Explanation:

Distance from mic 1 to origin = 3 m

Distance from mic 2 to origin = 5 m

Speed of sound = 343 m/s

Time taken by mic 1

t_1=\frac{\text{Distance from mic 1 to origin}}{\text{Speed of sound}}\\\Rightarrow t_1=\frac{3}{343}=0.008746\ s

t_2=\frac{\text{Distance from mic 2 to origin}}{\text{Speed of sound}}\\\Rightarrow t_2=\frac{5}{343}=0.014577\ s

Time difference = t₂ - t₁ = 0.14577-0.008746 = 0.00583 s

∴ Difference in time taken by the speaker is 0.00583 s

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q_{flux} = Q_{conduction} \\\\q_{flux}  = \frac{K(T_1 - T_2)}{L}\\\\q_{flux}  = \frac{2.79(50 - 35.5)}{0.2}\\\\q_{flux} = 202.3W/m^2

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