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Anna11 [10]
3 years ago
9

How much force, in g cm/s2

Physics
2 answers:
scoray [572]3 years ago
3 0
In this question force is measured in  g cm/s2 so we know that to get the answer we times g by cm/s2 
50 × 20 = 1000
Vinvika [58]3 years ago
3 0

Answer:

F=1000\frac{gr \times cm}{s^{2} }

Explanation:

Givens

m=50g

a=20cm/s^{2}

To find the force exerted by the golf ball, we need to use Netwon's second law, which is defined as

F=ma

In words, when we apply a force to an object with mass m, the object will accelerate at a.

Now, replacing all given values, we have

F=ma\\F=50g(20cm/s^{2} )\\F=1000\frac{gr \times cm}{s^{2} }

Therefore, the force exerted by the golf ball is F=1000\frac{gr \times cm}{s^{2} }

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kobusy [5.1K]

Answer:When prfessionals take data collections its important becasue it can cause error. Lets say they are sloppy with thier work and end up getting something that is not near what should be happening. This can have a major affect on the truth of what they are doing and an effect on thier end result in general.

Explanation:

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As waves get closer to the beach they increase in energy
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3 years ago
Hans Full is pulling on a rope to drag his backpack to school across the ice. He pulls upwards and rightwards with a force of 22
natka813 [3]

Answer:

2420 J

Explanation:

From the question given above, the following data were obtained:

Force (F) = 22.9 N

Angle (θ) = 35°

Distance (d) = 129 m

Workdone (Wd) =?

The work done can be obtained by using the following formula:

Wd = Fd × Cos θ

Wd = 22.9 × 129 × Cos 35

Wd = 22.9 × 129 × 0.8192

Wd ≈ 2420 J

Thus, the workdone is 2420 J.

3 0
3 years ago
A wall in a house contains a single window. The window consists of a single pane of glass whose area is 0.15 m2 and whose thickn
KengaRu [80]

Answer:

88 %

Explanation:

The rate of heat loss by a conducting material of thermal conductivity K, cross-sectional area,A and thickness d with a temperature gradient ΔT is given by

P = KAΔT/d

The total heat lost by the styrofoam wall is P₁ = K₁A₁ΔT₁/d₁ where K₁ =thermal conductivity of styrofoam wall 0.033 W/m-K, A₁ = area of styrofoam wall = 17 m², ΔT₁ = temperature gradient between inside and outside of the wall and d₁ = thickness of styrofoam wall = 0.20 m

The total heat lost by the glass window is P₂ = K₂A₂ΔT₂/d₂ where K₂ =thermal conductivity of glass window pane wall 0.96 W/m-K, A₂ = area of glass window pane = 0.15 m², ΔT₂ = temperature gradient between inside and outside of the window and d₂ = thickness of glass window pane = 7 mm = 0.007 m

The total heat lost is P = P₁ + P₂ = K₁A₁ΔT₁/d₁ + K₂A₂ΔT₂/d₂

Now, since the temperatures of both inside and outside of both window and wall are the same, ΔT₁ = ΔT₂ = ΔT

So, P = K₁A₁ΔT/d₁ + K₂A₂ΔT/d₂

Since P₂ = K₂A₂ΔT₂/d₂ = K₂A₂ΔT/d₂is the heat lost by the window, the fraction of the heat lost by the window from the total heat lost is

P₂/P = K₂A₂ΔT/d₂ ÷ (K₁A₁ΔT/d₁ + K₂A₂ΔT/d₂)

= 1/(K₁A₁ΔT/d₁÷K₂A₂ΔT/d₂ + 1)

= 1/(K₁A₁d₂÷K₂A₂d₁ + 1)

= 1/[(0.033 W/m-K × 17 m² × 0.007 m ÷ 0.96 W/m-K × 0.15 m² × 0.20 m) + 1]

= 1/(0.003927/0.0288 + 1)

= 1/(0.1364 + 1)

= 1/1.1364

= 0.88.

The percentage is thus P₂/P × 100 % = 0.88 × 100 % = 88 %

The percentage of heat lost by window of the total heat is 88 %

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3 years ago
The irreversible thermite reaction (Fe2O3 + 2 Al --> 2 Fe + Al2O3) is highly exothermic, changing the temperature by over 100
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Answer:

the water will boil and change into a gas

Explanation:

This is because it is exothermic and releases the energy into the surroundings and the fact that water boils at 100 degrees Celsius

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