All categories

2 years ago

In 2-3 complete sentences, explain the relationship between speed, frequency, and wavelength.

1 answer:

7 0

The relationship of the speed of sound, its frequency, and wavelength is the same as for all waves: vw = fλ, where vw is the speed of sound, f is its frequency, and λ is its wavelength. ... The frequency is the same as that of the source and is the number of waves that pass a point per unit time.

You might be interested in

A 2.0-cm-diameter parallel-plate capacitor with a spacing of 0.50 mm is charged to 200 V. What are (a) the total energy stored i

Debora [2.8K]

Answer:

(A) Total energy will be equal to $0.044\times 10^{-5}J$

(b) Energy density will be equal to $0.0175J/m^3$

Explanation:

We have given diameter of the plate d = 2 cm = 0.02 m

So area of the plate $A=\pi r^2=3.14\times 0.02^2=0.001256m^2$

Distance between the plates d = 0.50 mm = $0.50\times 10^{-3}m$

Permitivity of free space $\epsilon _0=8.85\times 10^{-12}F/m$

Potential difference V =200 volt

Capacitance between the plate is equal to $C=\frac{\epsilon _0A}{d}=\frac{8.85\times 10^{-12}\times 0.001256}{0.50\times 10^{-3}}=0.022\times 10^{-9}F$

(a) Total energy stored in the capacitor is equal to

$E=\frac{1}{2}CV^2$

$E=\frac{1}{2}\times 0.022\times 10^{-9}\times 200^2=0.044\times 10^{-5}J$

(b) Volume will be equal to $V=Ad$ , here A is area and d is distance between plates

$V=0.001256\times 0.02=2.512\times 10^{-5}m^3$

So energy density $=\frac{Energy}{volume}=\frac{0.044\times 10^{-5}}{2.512\times 10^{-5}}=0.0175J/m^3$

7 0

3 years ago

The Hubble Space Telescope in orbit above the Earth has a 2.4 m circular aperture. The telescope has equipment for detecting ult

strojnjashka [21]

Answer:

Option d

The minimum angular separation between two objects that the Hubble Space Telescope can resolve is $4.8x10^{-8}rad$ .

Explanation:

The resulting image in a telescope that will be gotten from an object is a diffraction pattern instead of a perfect point (point spread function (PSF)).

That diffraction pattern is gotten because the light encounters different obstacles on its path inside the telescope (interacts with the walls and edges of the instrument).

The diffraction pattern is composed by a central disk, called Airy disk, and diffraction rings.

The angular resolution is defined as the minimal separation at which two sources can be resolved one for another, or in other words, when the distance between the two diffraction pattern maxima is greater than the radius of the Airy disk.

The angular resolution can be determined in analytical way by means of the Rayleigh criterion.

$\theta = 1.22\frac{\lambda}{D}$ (1)

Where $\lambda$ is the wavelength and D is the diameter of the telescope.

Notice that it is necessary to express the wavelength in the same units than the diameter.

$\lambda = 95nm \cdot \frac{1x10^{-9}m}{1nm}$ ⇒ $9.5x10^{-8}m$

Finally, equation 1 can be used.

$\theta = 1.22(\frac{9.5x10^{-8}m}{2.4m})$

$\theta = 4.8x10^{-8}rad$

Hence, the minimum angular separation between two objects that the Hubble Space Telescope can resolve is $4.8x10^{-8}rad$ .

5 0

3 years ago

What is the length of the hypotenuse of a right triangle, whose legs have lengths of 12 meters and 35 meters?

Makovka662 [10]

The answer is 37 cause the two sides squared and added together equals the hypotenuse squared after that you just find the square root of the answer

5 0

3 years ago

Read 2 more answers

With what speed must m1 rotate in a circle of radius r if m2 is to remain hanging at rest?

11Alexandr11 [23.1K]

Velocity =2 pie*r/t
distance = 2 (pie) r
accelaretion =distance/t2
f=m*v2/r
v=square root of Fr/m

5 0

3 years ago

Nabil wants to work out the density of a pebble. he has a displacement can and a beaker. What other piece of equipment will he n

Svetllana [295]

Answer:

1) Measuring cylinder

2) Top Pan Balance

Explanation:

To find the density of the pebble Nabil should first accurately measure the mass of the pebble using the top pan balance

He should then fill the displacement can till the water reaches the outlet pipe at the to of the cylinder

He should then place the pebble into the cylinder carefully ans allow the water that would start coming out to stop

The volume of water in the displaced cylinder is then measured and the density is found by dividing the mass of the pebble by the volume of water in the measuring cylinder

$Density \ of \ pebble = \dfrac{Pebble \ mass}{Volume \ of \ water \ in\ the \ measuring \ cylinder} = \dfrac{Pebble \ mass}{Water \ volume \ displaced}$

3 0

2 years ago