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sattari [20]
3 years ago
12

True or False: Buoyancy is an upwards force measured in Newtons.

Physics
2 answers:
Alex73 [517]3 years ago
6 0

Answer:

true

Explanation:

sashaice [31]3 years ago
5 0
That is true, buoyancy is an upwards force measured in newton’s
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yawa3891 [41]

Answer:

The molecules in hot air are moving faster than the molecules in cold air.

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The planet most like the earth in size and gravitation is:
Contact [7]

Answer:

Mars

Explanation:

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3 years ago
Read 2 more answers
Suppose a gliding 2-kg cart bumps into, and sticks to, a stationary 5-kg cart. If the speed of the gliding cart before the colli
Thepotemich [5.8K]

Answer:

Therefore,

Final velocity of the coupled carts after the collision is

v_{f}=4\ m/s

Explanation:

Given:

Mass of  Glidding Cart = m₁ = 2 kg

Mass of Stationary Cart = m₂ = 5 kg

Initial velocity of Glidding Cart = u₁ = 14 m/s

Initial velocity of Stationary Cart = u₂ = 0 m/s

To Find:

Final velocity of the coupled carts after the collision = v_{f}=?

Solution:

Law of Conservation of Momentum:

For a collision occurring between two objects in an isolated system, the total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision.

It is denoted by "p" and given by

Momentum = p = mass × velocity

Hence by law of Conservation of Momentum we hame

Momentum before collision = Momentum after collision

Here after collision both are stuck together so both will have same final velocity,

m_{1}\times u_{1}+m_{2}\times u_{2}=(m_{1}+m_{2})\times v_{f}

Substituting the values we get

2\times 14 + 5\times 0 =(2+5)\times v_{f}

v_{f}=\dfrac{28}{7}=4\ m/s

Therefore,

Final velocity of the coupled carts after the collision is

v_{f}=4\ m/s

8 0
3 years ago
A car which is traveling at a velocity of 1.6 m/s undergoes an acceleration of 9.2 m/s over a distance of 540 m. How fast is it
mixas84 [53]

Answer:

Vf = 99.7 m/s

Explanation:

In order to find the final velocity of the car, we will use the third equation of motion. The third equation of motion is given as follows:

2as = V_{f}^{2} - V_{i}^{2}

where,

a = acceleration of the car = 9.2 m/s²

s = distance traveled by the car = 540 m

Vf = Final Speed of the car = ?

Vi = Initial Speed of the car  1.6 m/s

2(9.2\ m/s^{2})(540\ m) = (V_{f})^{2}-(1.6\ m/s)^{2}\\V_{f}^{2} = 9936\ m^{2}/s^{2} + 2.56\ m^{2}/s^{2}\\\\V_{f} = \sqrt{9938.56\ m^{2}/s^{2}}

<u>Vf = 99.7 m/s</u>

8 0
3 years ago
Definition of graph?
xeze [42]

<u>Answer:</u>

1. A graph is defined as <em>" A Diagram represents a system of connections or interrelations among two or more things by a number of different dots, lines etc".</em>

2. In simple words <em>"Graph is a representation of any object or a physical structure by dots, lines, etc.</em>

6 0
3 years ago
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