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vladimir1956 [14]
3 years ago
10

5. A 1.2 m guitar string is under a tension of 888 N. The waves produced on the string (when

Physics
1 answer:
Usimov [2.4K]3 years ago
4 0
I don’t even know tbh
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Jenny and Alyssa are members of the cross-country team. On a training run, Jenny starts off and runs at a constant 3.8 m/s. Alys
guapka [62]

Answer:

285 seconds

Explanation:

Jenny speed is 3.8 m/s

Alyssa speed in 4.0 m/s

Alyssa starts after 15 seconds

Find the distance covered by Jenny, when Alyssa starts

Distance=Speed*time

Distance covered by Jenny in 15 seconds= 3.8×15=57m

Relative speed of the two members heading same direction will be;

4.0m/s-3.8m/s=0.2m/s

To find the time Alyssa catch up with Jenny you divide the distance to be covered by Alyssa by the relative speed of the two

Distance=57m, relative speed=0.2m/s  t=57/0.2 =285 seconds

=4.75 minutes

5 0
3 years ago
Read 2 more answers
The work energy principle states that the change in kinetic energy of an object is equal to the net work done on the object. If
sattari [20]

Answer:

v=\sqrt{2gh}\ m/s

Explanation:

From work energy theorem

Work done by all forces = Change in kinetic energy

Lets take

m= mass of object

h=height from the ground surface

initial velocity of object = 0 m/s

The final velocity of object is v

Work done by gravitational force = m g . h

The final kinetic energy = 1/2 m v²

So

Work done by all forces = Change in kinetic energy

m g h =  1/2 m v² - 0

v² = 2 g h

v=\sqrt{2gh}\ m/s

6 0
3 years ago
HELP ASAP <br> Will mark brainliest if it is correct.
lisabon 2012 [21]

Answer:

Answer: It allows people to rapidly heat items

Hope this helps!

Explanation:

8 0
3 years ago
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Determine experimentally which rotational axis yields the maximum rotational inertia (i.e., moment of inertia) and which yields
Law Incorporation [45]

Answer:

  the maximum is I₁ axis of rotation at the end

     the minimum moment is I₂ axis of rotation at the center of mass

Explanation:

For this exercise we use the definition moment of inertia

          I = ∫ r² dm

for bodies of high symmetry it is tabulated; In this case we can approximate a broomstick to a thin rod, the moment of inertia with respect to a perpendicular axis when varying are

at one end

           I₁ = ⅓ mL²

in in center

           I₂ = \frac{1}{12} m L²

There is another possible axis of rotation around the axis of the broom, in this case we have a solid cylinder

           I₃ = \frac{1}{2} m r²

remember that the diameter of the broom is much smaller than its length, therefore this moment of inertia is very small

when examining the different moments of inertia:

     the maximum is I₁ axis of rotation at the end

     the minimum moment is I₂ axis of rotation at the center of mass

3 0
3 years ago
Reese can run 10 meter in 5 seconds.What is her speed?
Bad White [126]

Answer:

2 meters per second

Explanation:

4 0
3 years ago
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