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3 years ago

PLEASE HELP DUE IN 1 HOUR, AND PLEASE DON'T PUT THOSE LINKS OR ELSE I WILL REPORT YOU.

Mathematics

2 answers:

Mnenie [13.5K]3 years ago

6 0

Answer:

Step-by-step explanation:

m≥150

draw a solid dot (since it is greater than or equal to) starting at 150 and continue to the end of the number line.

Nikolay [14]3 years ago

4 0

Answer:

B. m is greater than or equal to 150

Step-by-step explanation:

if he has to drive at least 150, then he must drive 150 miles or more

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Members of a community center are planning a field trip to the zoo. More than 50 people will go on the trip. Ten people are prov

slava [35]

The answer is 5(k+10)>50

6 0

3 years ago

Read 2 more answers

What's the range of the function y= -2(2)^x+2

Aleksandr [31]

Answer:

Step-by-step explanation:

Simply substitute the x and y values into the equation, Infinity is a number that gets closer & closer to zero and the y-intercept is always 2.

Infinity is a number that gets closer & closer to zero and the y-intercept is always 2.

y=-2(2)(-infity)+2

y=2

4 0

2 years ago

Please consider the following values for the variables X and Y. Treat each row as a pair of scores for the variables X and Y (wi

Studentka2010 [4]

Answer:

The Pearson's coefficient of correlation between the is 0.700.

Step-by-step explanation:

The correlation coefficient is a statistical degree that computes the strength of the linear relationship amid the relative movements of the two variables (i.e. dependent and independent).It ranges from -1 to +1.

The formula to compute correlation between two variables <em>X</em> and <em>Y</em> is:

$r(X, Y)=\frac{Cov(X, Y)}{\sqrt{V(X)\cdot V(Y)}}$

The formula to compute covariance is:

$Cov(X, Y)=n\cdot \sum XY-\sum X \cdot\sum Y$

The formula to compute the variances are:

$V(X)=n\cdot\sum X^{2}-(\sum X)^{2}\\V(Y)=n\cdot\sum Y^{2}-(\sum Y)^{2}$

Consider the table attached below.

Compute the covariance as follows:

$Cov(X, Y)=n\cdot \sum XY-\sum X \cdot\sum Y$

$=(5\times 165)-(30\times 25)\\=75$

Thus, the covariance is 75.

Compute the variance of X and Y as follows:

$V(X)=n\cdot\sum X^{2}-(\sum X)^{2}\\=(5\times 226)-(30)^{2}\\=230\\\\V(Y)=n\cdot\sum Y^{2}-(\sum Y)^{2}\\=(5\times 135)-(25)^{2}\\=50$

Compute the correlation coefficient as follows:

$r(X, Y)=\frac{Cov(X, Y)}{\sqrt{V(X)\cdot V(Y)}}$

$=\frac{75}{\sqrt{230\times 50}}$

$=0.69937\\\approx0.70$

Thus, the Pearson's coefficient of correlation between the is 0.700.

5 0

3 years ago

Can someone help me????

SpyIntel [72]

Lemme think bout it....no

5 0

3 years ago

Darren spent 4 /2 hours on his homework on Monday. On Tuesday, he spent 2 31shours on his

guapka [62]

Answer: 4 hours 31 min

Step-by-step explanation: first you need to simplify or solve 4/2 which is 2 because 4 divided by 2 is 2 and on Tuesday he spent 2 hours and 31 min no simply add 2 hours plus 2 hours and 31 min which gives you 4 hours and 31 min

3 0

3 years ago