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SOVA2 [1]
3 years ago
10

10 points! Please help if you know the answer I need to get 100% on this test :)

Chemistry
1 answer:
miskamm [114]3 years ago
7 0

Answer:

Metal has an high capacity, which allows it to heat up faster and transfer the heat to the contents of the pot or pan.

Explanation:

Because metal pots are made from a narrow range of metals because pots and pans need to conduct heat well.

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What is the formula for an ionic compound with these pairs of ions? (NH4+, N-3)
nlexa [21]

Answer:NH4NO3

Explanation:

5 0
3 years ago
Read 2 more answers
4. Energy can be conserved by -
mart [117]

Energy can be conserved by efficient energy use.

Answer: Option A

<u>Explanation:</u>

Energy can be transferred from one form to another, but it cannot be destroyed or created. So it can be conserved if efficiently used. Thus efficient usage of energy lead to conservation of energy. Due to conservation of energy, the forces can be renewable and non-renewable.

So, we should know how the input energy can be completely converted to another form of energy leading to efficient usage of energy without any loss. As if there is no loss, input energy will be equal to output energy leading to 100% efficiency.

4 0
4 years ago
What is the energy released in the fission reaction 1 0 n + 235 92 U → 131 53 I + 89 39 Y + 16 1 0 n 0 1 n + 92 235 U → 53 131 I
mihalych1998 [28]

<u>Answer:</u> The energy released in the given nuclear reaction is 94.99 MeV.

<u>Explanation:</u>

For the given nuclear reaction:

_{92}^{235}\textrm{U}+_0^1\textrm{n}\rightarrow _{53}^{131}\textrm{I}+_{39}^{89}\textrm{Y}+16_{0}^1\textrm{n}

We are given:

Mass of _{92}^{235}\textrm{U} = 235.043924 u

Mass of _{0}^{1}\textrm{n} = 1.008665 u

Mass of _{53}^{131}\textrm{I} = 130.9061246 u

Mass of _{39}^{89}\textrm{Y} = 88.9058483 u u

To calculate the mass defect, we use the equation:

\Delta m=\text{Mass of reactants}-\text{Mass of products}

Putting values in above equation, we get:

\Delta m=(m_U+m_{n})-(m_{I}+m_{Y}+16m_{n})\\\\\Delta m=(235.043924+1.008665)-(130.9061246+88.9058483+16(1.008665))=0.1019761u

To calculate the energy released, we use the equation:

E=\Delta mc^2\\E=(0.1019761u)\times c^2

E=(0.1019761u)\times (931.5MeV)  (Conversion factor:  1u=931.5MeV/c^2  )

E=94.99MeV

Hence, the energy released in the given nuclear reaction is 94.99 MeV.

3 0
3 years ago
What is the ph for hcl and ch3cooh?
Maurinko [17]
HCL - 3.01
CH3COOH -2.4
5 0
4 years ago
it takes 26.23 mL of a 1.008 M NaOh solution to neutralize a solution of an unknown monoprotic acid in 150.2 mL of solution. Wha
ASHA 777 [7]

Answer:

.176 M

Explanation:

set the number of moles of the base equal to the number of moles of acid.

(1.008 mol/L)(26.23 x 10^-3 L)=(150.2x10^-3 L)(x)

x = .176030892 mol/L

8 0
3 years ago
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