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3 years ago

PLEASE HELP LOVELIES?? xxx

Mathematics

1 answer:

Lelechka [254]3 years ago

4 0

The data set has no association.

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Pls i need an answer now

Elena-2011 [213]

Answer:

Step-by-step explanation:

1. 5, 3.5, $\sqrt{9\\}$ , $-\frac{12}{5}$ , -7

2. 10, π ,3.1415, 0, -10

3. 1 $\frac{1}{2}$ , 1.44, 1.4(3), 1.(43), $\frac{7}{5}$

6 0

2 years ago

A lab technician cuts a 15 in piece of glass tubing into two pieces. One piece is 7 in longer than the other. How long are the

zysi [14]

Answer:

2.1 in

Step-by-step explanation:

I only wrote the expression 7n = 15. Then figured it out from there. I ended up with n = 2.1

I'm sorry if this doesn't help. I tried my best to solve it. Hope this leads you to the right answer ^^

8 0

1 year ago

A ball will be drawn from the bag containing 20 balls numbered one through 20 if each ball is equally likely to be drawn what is

son4ous [18]

Answer:

3/5

Step-by-step explanation:

There are 20 balls, numbered 1 through 20.

Of these, 10 are even, 4 are less than five, and 2 are both even and less than 5.

So the probability is:

P(even or <5) = P(even) + P(<5) − P(even and <5)

P(even or <5) = 10/20 + 4/20 − 2/20

P(even or <5) = 12/20

P(even or <5) = 3/5

5 0

2 years ago

For what value of constant c is the function k(x) continuous at x = 0 if k =

nlexa [21]

The value of constant c for which the function k(x) is continuous is zero.

<h3>What is the limit of a function?</h3>

The limit of a function at a point k in its field is the value that the function approaches as its parameter approaches k.

To determine the value of constant c for which the function of k(x) is continuous, we take the limit of the parameter as follows:

$\mathbf{ \lim_{x \to 0^-} k(x) = \lim_{x \to 0^+} k(x) = 0 }$

$\mathbf{\implies \lim_{x \to 0 } \ \ \dfrac{sec \ x - 1}{x}= c }$

Provided that:

$\mathbf{\implies \lim_{x \to 0 } \ \ \dfrac{sec \ x - 1}{x}= \dfrac{0}{0} \ (form) }$

Using l'Hospital's rule:

$\mathbf{\implies \lim_{x \to 0} \ \ \dfrac{\dfrac{d}{dx}(sec \ x - 1)}{\dfrac{d}{dx}(x)}= \lim_{x \to 0} sec \ x \ tan \ x = 0}$

Therefore:

$\mathbf{\implies \lim_{x \to 0 } \ \ \dfrac{sec \ x - 1}{x}=0 }$

Hence; c = 0

Learn more about the limit of a function x here:

brainly.com/question/8131777

#SPJ1

5 0

1 year ago

5/ 2 x ≤ -14<br><br> A. -10.3<br> B. -6<br> C. -5.6<br> D. -5

Advocard [28]

Answer:

Step-by-step explanation:

5/2x<_-14

5x<_-28

5x/5<_-28/6

X<_-5.6

4 0

2 years ago

Read 2 more answers