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3 years ago

The value of 8 in 56982 is how many times larger than the value of 8 in 156408

Mathematics

2 answers:

Marysya12 [62]3 years ago

8 0

The value of 8 in 56982 is 10times larger than the value of 8 in 156408

Len [333]3 years ago

3 0

The value of 8 in '56982' is 80 whereas the value of 8 in '156408' is just 8 so the value of the 8 in 56982 is x10 larger than the value of 8 in 156408.
Hope this helps x

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HELP ASAP ILL GIVE BRAINLIST

Mila [183]

Answer:

Part A) ΔCGB and ΔPBE are similiar

Part B) They are similar because they are Vertical Angles/Alternate Interior Angles

Part C) Distance from B to E is 125; Distance from P to E is 275.

Step-by-step explanation:

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2 years ago

10) A rhombus has a diagonal 8.6 mm long and an area of 81.7 mm. what is the perimeter?

BaLLatris [955]

Answer:

P=41.72

Step-by-step explanation:

S=ACxDB/2

81.7=8.6xDB/2

81.7=4.3xDB|:4.3

19(mm)=DB

DO=19/2=9.5

OC=8.6/2=4.3

(O is the center of the rhombus, where two diagonals meet)

a²+b²=c² (DO²+OC²=DC²)

9.5²+4.3²=c²

90.25+18,49=c²

√108,74=√c²

c≈10.43

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P=4x10.43

P=41.72

Hope it helps:)

6 0

1 year ago

What is the value of X?

Pavel [41]

Step-by-step explanation:

$x = 2 \times 52.5 \degree \\ x = 105 \degree$

4 0

2 years ago

Read 2 more answers

If ay = 9 and an = -5an-1 + 5 then find the value of az. Answer: Submit Answer

Butoxors [25]

The answer would be 10 because 9+-5=4+-1=5+5=10

5 0

3 years ago

Semicircles

Studentka2010 [4]

Answer:

The area of the shaded portion of the figure is $9.1\ cm^2$

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The shaded area is equal to the area of the square less the area not shaded.

There are 4 "not shaded" regions.

step 1

Find the area of square ABCD

The area of square is equal to

$A=b^2$

where

b is the length side of the square

we have

$b=4\ cm$

substitute

$A=4^2=16\ cm^2$

step 2

We can find the area of 2 "not shaded" regions by calculating the area of the square less two semi-circles (one circle):

The area of circle is equal to

$A=\pi r^{2}$

The diameter of the circle is equal to the length side of the square

$r=\frac{b}{2}=\frac{4}{2}=2\ cm$ ---> radius is half the diameter

substitute

$A=\pi (2)^{2}$

$A=4\pi\ cm^2$

Therefore, the area of 2 "not-shaded" regions is:

$A=(16-4\pi) \ cm^2$

and the area of 4 "not-shaded" regions is:

$A=2(16-4\pi)=(32-8\pi)\ cm^2$

step 3

Find the area of the shaded region

Remember that the area of the shaded region is the area of the square less 4 "not shaded" regions:

$A=16-(32-8\pi)=(8\pi-16)\ cm^2$

---> exact value

assume

$\pi =3.14$

substitute

$A=(8(3.14)-16)=9.1\ cm^2$

8 0

3 years ago