Graph the image of the given triangle after the transformation with the rule (x, y)→(x+3, y−5) .
The vertices of given triangle ABC is
A(2,2) B(7,3) and C(4,-3)
rule (x, y)→(x+3, y−5) , add 3 with x and subtract 5 from y.
A(2,2) becomes (2+3, 2-5) => (5,-3)
B(7,3) becomes (7+3, 3-5) => (10,-2)
C(4,-3) becomes (4+3, -3-5) => (7,-8)
So the vertices of triangle after transformation is
A'(5,-3) B'(10,-2) C' (7,-8)
The graph is attached below