1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sergeeva-Olga [200]
2 years ago
6

A golf ball with a mass of 46 grams will accelerate five times as fast as a

Chemistry
2 answers:
ELEN [110]2 years ago
6 0

Answer:

Newtons first law

Explanation:

focre=mass x acceleration

I am Lyosha [343]2 years ago
4 0
I believe that the answer above mine is wrong. Newton’s second law states that force = mass x acceleration, not the first. This is an example of Newton’s SECOND Law. Hope this helps
You might be interested in
One mole of copper(ii) sulfate, cuso4, contains ________ o atoms.
Ierofanga [76]
According  to  avogadro   constant,  the  number  of  units  in  one  mole  of  any  substance   contain  6.022  x10  ^23  atoms

therefore  the  number  of  o  atoms  in   one  mole  of    CuSO4  =  6.022 x 10 ^ 23
6 0
3 years ago
Read 2 more answers
HELP ME ON NUMBER 8 ASAP
Varvara68 [4.7K]

Answer:

2. hope it helps. please follow me I'm new here

3 0
3 years ago
(a) Compute the radius r of an impurity atom that will just fit into an FCC octahedral site in terms of the atomic radius R of t
11Alexandr11 [23.1K]

Answer:

a

The radius of an impurity atom occupying FCC octahedral site is 0.414{\rm{R}}

b

The radius of an impurity atom occupying FCC tetrahedral site is 0.225{\rm{R}} .

Explanation:

In order to get a better understanding of the solution we need to understand that the concept used to solve this question is based on the voids present in a unit cell. Looking at the fundamentals

An impurity atom in a unit cell occupies the void spaces. In FCC type of structure, there are two types of voids present. First, an octahedral void is a hole created when six spheres touch each other usually placed at the body center. On the other hand, a tetrahedral void is generated when four spheres touch each other and is placed along the body diagonal.

Step 1 of 2

(1)

The position of an atom that fits in the octahedral site with radius \left( r \right)is as shown in the first uploaded image.

In the above diagram, R is the radius of atom and a is the edge length of the unit cell.

The radius of the impurity is as follows:

2r=a-2R------(A)

The relation between radius of atom and edge length is calculated using Pythagoras Theorem is shown as follows:

Consider \Delta {\rm{XYZ}} as follows:

(XY)^ 2 =(YZ) ^2 +(XZ)^2

Substitute XY as{\rm{R}} + 2{\rm{R + R}} and {\rm{YZ}} as a and {\rm{ZX}} as a in above equation as follows:

(R+2R+R) ^2 =a ^2 +a^ 2\\16R ^2 =2a^ 2\\ a =2\sqrt{2R}

Substitute value of aa in equation (A) as follows:

r= \frac{2\sqrt{2}R -2R }{2} \\ =\sqrt{2} -1R\\ = 0.414R

The radius of an impurity atom occupying FCC octahedral site is 0.414{\rm{R}}

Note

An impure atom occupies the octahedral site, the relation between the radius of atom, edge length of unit cell and impure atom is calculated. The relation between the edge length and radius of atom is calculated using Pythagoras Theorem. This further enables in finding the radius of an impure atom.  

Step 2 of 2

(2)

The impure atom in FCC tetrahedral site is present at the body diagonal.

The position of an atom that fits in the octahedral site with radius rr is shown on the second uploaded image :

In the above diagram, R is the radius of atom and a is the edge length of the unit cell.

The body diagonal is represented by AD.

The relation between the radius of impurity, radius of atom and body diagonal is shown as follows:

AD=2R+2r----(B)

   In    \Delta {\rm{ABC}},

(AB) ^2 =(AC) ^2 +(BC) ^2

For calculation of AD, AB is determined using Pythagoras theorem.

Substitute {\rm{AC}} as a and {\rm{BC}} as a in above equation as follows:

(AB) ^2 =a ^2 +a ^2

AB= \sqrt{2a} ----(1)

Also,

AB=2R

Substitute value of 2{\rm{R}} for {\rm{AB}} in equation (1) as follows:

2R= \sqrt{2} aa = \sqrt{2} R

Therefore, the length of body diagonal is calculated using Pythagoras Theorem in \Delta {\rm{ABD}} as follows:

(AD) ^2 =(AB) ^2 +(BD)^2

Substitute {\rm{AB}} as \sqrt 2a   and {\rm{BD}} as a in above equation as follows:

(AD) ^2 =( \sqrt 2a) ^2 +(a) ^2 AD= \sqrt3a

For calculation of radius of an impure atom in FCC tetrahedral site,

Substitute value of AD in equation (B) as follows:

\sqrt 3a=2R+2r

Substitute a as \sqrt 2{\rm{R}} in above equation as follows:

( \sqrt3 )( \sqrt2 )R=2R+2r\\\\

r = \frac{2.4494R-2R}{2}\\

=0.2247R

\approx 0.225R

The radius of an impurity atom occupying FCC tetrahedral site is 0.225{\rm{R}} .

Note

An impure atom occupies the tetrahedral site, the relation between the radius of atom, edge length of unit cell and impure atom is calculated. The length of body diagonal is calculated using Pythagoras Theorem. The body diagonal is equal to the sum of the radii of two atoms. This helps in determining the relation between the radius of impure atom and radius of atom present in the unit cell.

7 0
3 years ago
2. Determine the new volume of a gas that begins at 2.3 L and changes
Snezhnost [94]
Answer: 2,012
BRAINLIST?
4 0
2 years ago
some infrared radiation reaches earth and sum does not with part does reach earth longer wave length or short wave length
Ede4ka [16]
The answer is long wave length because long wave lengths contians less energy, and would not harm living things such as plants and animals. the more engey a wave length has, the less harmful it is.

short wave length: lots of energy, extremely hot. (examples: gamma rays, and UV (ultraviolet) rays.

long wave lengths: not much energy, safe for humans and other life on Earth.

hopefully this helps.

4 0
3 years ago
Other questions:
  • What do you predict would happen if you conducted this experiment using sulfur hexafluoride (sf6) which is much heavier than met
    11·1 answer
  • What is carbon fixation?
    6·1 answer
  • What happens when you regurgitate?
    9·1 answer
  • Which atom will form an ionic bond with a Br atom?
    5·2 answers
  • What solution is placed when plating metal with gold?
    10·2 answers
  • When the procedure calls for making a more dilute solution of an acid, or mixing an acid with other solutions, what is the corre
    9·1 answer
  • What factors affect the dynamic state of equilibrium in a chemical reaction and how?
    6·1 answer
  • When a match burns it's mass decreases. Is this a violation of the law of conservation of mass?
    7·2 answers
  • Ammonia reacts with hypobromite OBr- as follows: NH3 OBr- ---> N2 Br- H20 which is the limiting reactant if 5.00 ml of 0.623
    13·1 answer
  • I’ll give brainliest!! I am a flat surface with one higher than the other. I make moving loads
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!