Can anyone do this for me? ty <3
2 answers:
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The right triangle is assumed to be inscribed in the rectangle, such that
hypotenuse is the diagonal of the rectangle.
- The length of the hypotenuse of the triangle is <u>26 cm</u>.
Reasons:
Let <em>x</em> and<em> </em><em>y</em> represent the length of the sides of the rectangle
Whereby the base and height of the right triangle are the same as the
length and width of the rectangle, we have;
Perimeter of the rectangle = 2·x + 2·y = 68
Therefore;
x + y = 34
The base of the right triangle = x
The height of the right triangle = y
By Pythagoras's theorem, the length of the hypotenuse side = √(x² + y²)
Therefore; Perimeter of the right triangle = x + y + √(x² + y²) = 60
Which gives;
∴√(x² + y²) = 60 - (x + y) = 60 - 34 = 26
The length of the hypotenuse side, √(x² + y²) = <u>26 cm</u>
Learn more about Pythagoras's theorem here:
To solve for p, square both sides and move the equation to one side is equal to zero. Then factor. I chose -2 and -5 because -2 x -5 = 10 and -2 + -5 = -7. After factoring, solve p-5=0 and p-2=0. When one of those equals zero then the equation (p-5)(p-2)=0 is true.
