Answer:
Fluorine is much more reactive than chlorine (despite the lower electron affinity) because the energy released in other steps in its reactions more than makes up for the lower amount of energy released as electron affinity.
Explanation:
Answer: option C.Water will move into the cell
Explanation:
1) Start by analyzing what the statement means in terms of relative concentrations:
------------------------ | inside the cell ------------ | outside the cell |
sugar --------------- | higher ----------------------- | lower ------------- |
water -------------- | lower ------------------------- | higher ------------ |
2) Osmosis is the process where a barrier (the celll membrane) permits the pass of some component and not others.
The component that can pass is that whose particles are smaller. Sugar molecules (the solute) are bigger than water molecules (the solvent), so sugar molecules cannot pass the cell membrane. Only water can.
3) The driviing force for the motion of water molecules is called diffusion. The diffusion occurs from higher concentrations to lower concentrations.
Hence, the water molecules will from outside the outiside the cell, where they have the greater concentration, toward the inside of the cell, where water hasa the lower concentration.
As result, the water will move into the cell, which is the option C.
Answer:
The molecular formula of the compound :
Explanation:
The empirical formula of the compound =
The molecular formula of the compound =
The equation used to calculate the valency is :
We are given:
Mass of molecular formula = 86 g/mol
Mass of empirical formula = 43 g/mol
Putting values in above equation, we get:
The molecular formula of the compound :
Here we have to calculate the amount of 
ion present in the sample.
In the sample solution 0.122g of ion is present.
The reaction happens on addition of excess BaCl₂ in a sample solution of potassium sulfate (K₂SO₄) and sodium sulfate [(Na)₂SO₄] can be written as-
K₂SO₄ = 2K⁺ +
(Na)₂SO₄=2Na⁺ +
Thus, BaCl₂+ = BaSO₄↓ + 2Cl⁻ .
(Na)₂SO₄ and K₂SO₄ is highly soluble in water and the precipitation or the filtrate is due to the BaSO₄ only. As a precipitation appears due to addition of excess BaCl₂ thus the total amount of ion is precipitated in this reaction.
The precipitate i.e. barium sulfate (BaSO₄)is formed in the reaction which have the mass 0.298g.
Now the molecular weight of BaSO₄ is 233.3 g/mol.
We know the molecular weight of sulfate ion () is 96.06 g/mol. Thus in 1 mole of BaSO₄ 96.06 g of ion is present.
Or. we may write in 233.3 g of BaSO₄ 96.06 g of ion is present. So in 1 g of BaSO₄ 
g of ion is present.
Or, in 0.298 g of the filtered mass (0.298×0.411)=0.122g of ion is present.
Answer:
can you provide a picture?
