Answer:
Mass = 24.36 g of N₂
Explanation:
The balance chemical equation for the decomposition of NaNO₃ is as follow;
2 NaN₃ → 2 Na + 3 N₂
Step 1: Find moles of N₂ as;
According to equation,
2 moles of NaNO₃ produces = 3 moles of N₂
So,
0.58 moles of NaNO₃ will produce = X moles of N₂
Solving for X,
X = 3 mol × 0.58 mol / 2 mol
X = 0.87 mol of N₂
Step 2: Calculate mass of N₂ as,
Mass = Moles × M.Mass
Mass = 0.87 mol × 28.01 g/mol
Mass = 24.36 g of N₂
Answer:
28500 years
Explanation:
Applying,
A = A'(
)............... Equation 1
Where A = Original mass of Carbon-14, A' = Final mass of carbon-14 after decaying, x = total time, y = half-life.
From the question,
Given: A = 1 g, A' = 31.3 mg = 0.0313 g, y = 5700 years.
Substitute these values into equation 1
1 = 0.0313(
)
= 1/0.0313
= 31.95
≈ 32
≈ 2⁵
Equating the base and solve for x
x/5700 ≈ 5
x ≈ 5×5700
x ≈ 28500 years
An atom has a nucleus and is made up of protons neutrons and electrons
Bleach contains sodium chlorine and oxygen
Answer:
H₂ is excess reactant and O₂ the limiting reactant
Explanation:
Based on the chemical reaction:
2H₂(g) + O₂(g) → 2H₂O
<em>2 moles of H₂ react per mole of O₂</em>
<em />
To find limiting reactant we need to convert the mass of each reactant to moles:
<em>Moles H₂ -Molar mass: 2.016g/mol-:</em>
10g H₂ * (1mol / 2.016g) = 4.96 moles
<em>Moles O₂ -Molar mass: 32g/mol-:</em>
22g O₂ * (1mol / 32g) = 0.69 moles
For a complete reaction of 0.69 moles of O₂ are needed:
0.69mol O₂ * (2mol H₂ / 1mol O₂) = 1.38 moles of H₂
As there are 4.96 moles,
<h3>H₂ is excess reactant and O₂ the limiting reactant</h3>
