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exis [7]
3 years ago
10

What volume of 2.5% (m/v) KOH can be prepared from 125 mL of a 5.0% KOH solution?

Chemistry
1 answer:
TiliK225 [7]3 years ago
6 0

Hey there!:

According to lew of dilution :

M*V = M'*V'

Where :

M = concentration of stock solution =  5.0% ( m / V )

V = volume of stock solution = 125 mL

M' = concentration of dilute solution = 2.5% ( m/V)

V' = volume of dilute solution = ??

Plug the values  we get:

V' =  m*V / M'

V' =  5.0 * 125 / 2.5

V' = 625 / 2.5

V' = 250 mL

Therefore , the volume prepared is 250 mL


Hope that helps!



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1. You are pushing a heavy shopping cart full of water bottles with a constant force. The shopping cart has
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Answer:

F = 50 N

Explanation:

Given data:

Mass of car = 250 Kg

Acceleration of car = 0.20 m/s²

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F = m×a

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If the decomposition of a sample of k c l o 3 kclox3 produces 3. 29 g of o 2 ox2 , what was the mass (g) of the original sample?
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A decomposition reaction can be described as a chemical reaction wherein one reactant breaks down into or extra merchandise.

explanation:

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moles               2               2            3

molar mass    122.55        74.55    32

Given, Mass of O₂ = 3.29g ⇒ moles of O₂

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3 moles of O₂  produced by 2 moles of KClO₃

Therefore, 0.1028 moles of O₂  produced by (2*0.1028/3) = 0.06853 moles of Kclo₃

Mass of KClo₃ in original sample is = moles * molar mass

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A decomposition response occurs whilst one reactant breaks down into or extra merchandise. this may be represented through the general equation: XY → X+ Y. Examples of decomposition reactions consist of the breakdown of hydrogen peroxide to water and oxygen, and the breakdown of water to hydrogen and oxygen.

Learn more about decomposition here:-brainly.com/question/27300160

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Answer:

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