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3 years ago

What are the products obtained in the electrolysis of molten nai?

Chemistry

1 answer:

yanalaym [24]3 years ago

4 0

Answer is: sodium (Na) and iodine (I₂).

<span> First ionic bonds in this salt are separeted because of heat:
</span>NaI(l) → Na⁺(l) + I⁻(l).

Reaction of reduction at cathode(-): Na⁺(l) + e⁻ → Na(l) /×2.

2Na⁺(l) + 2e⁻ → 2Na(l).

Reaction of oxidation at anode(+): 2I⁻(l) → I₂(l) + 2e⁻.

The anode is positive and the cathode is negative.

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Chile~ i need help once again

tensa zangetsu [6.8K]

Answer:

Explanation:

8 0

3 years ago

Read 2 more answers

What is the hydrogen ion concentration of a solution with pH=8.25 ?

77julia77 [94]

Answer:

The answer is

<h2> $5.62 \times {10}^{ - 9} \: M$ </h2>

Explanation:

The pH of a solution can be found by using the formula

$pH = - log( {H}^{ + } )$

where

${H}^{ + }$ is the hydrogen ion concentration of the solution

From the question

pH = 8.25

The hydrogen ion concentration of the solution is

$8.25 = - log( {H}^{ + } )$

<u>Find antilog of both sides</u>

That's

${H}^{ + } = {10}^{ - 8.25} \\ = 5.62 \times {10}^{ - 9} \: M$

We have the final answer as

$5.62 \times {10}^{ - 9} \: M \\$

Hope this helps you

5 0

3 years ago

If 2 moles of salt is dissolved to form 1 liter of solution, what is the molarity of the solution?

Semenov [28]

Answer:

Explanation:

Molarity refers to the molar concentration of a solution. It can be calculated by using the formula as follows:

Molarity (M) = number of moles (n) ÷ volume (V)

Based on the information provided in this question, 2 moles of salt is dissolved to form 1 liter of solution. This means that n = 2mol, V = 1L

Molarity = n/V

Molarity = 2/1

Molarity = 2M

8 0

3 years ago

Please help/show work!

Keith_Richards [23]

Answer:

7.00335g

Explanation:

$n=\frac{V}{V_m} \\n = \frac{11.2}{22.4} \\n= 0.5 mol$

$n=\frac{m}{M} \\m=nM\\m=(0.5)(14.0067)\\m=7.00335g$

3 0

2 years ago

With the correct choice of acid, acid hydrolysis of ethanamide could produce A) ethanoic acid and ammonium chloride. B) ethanoic

Stells [14]

Answer:

A) Ethanoic acid and ammonium chloride.

Explanation:

Amides go through acid hydrolysis to produce carboxylic acid and ammonia by heating in aqueous acid. The acid hydrolysis reaction is produced through the <u>nucleophilic addition of water to the protonated amide</u>, then comes the transference of a proton from the oxygen to the nitrogen to make nitrogen a better leaving group, and finally, the subsequent elimination (see attachment).

In this case, the products formed with the reaction of ethanamide and aqueous HCl will be <u>ethanoic acid and ammonium chloride</u>.

7 0

3 years ago