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Taya2010 [7]
3 years ago
8

What are the products obtained in the electrolysis of molten nai?

Chemistry
1 answer:
yanalaym [24]3 years ago
4 0
Answer is: sodium (Na) and iodine (I₂).

<span> First ionic bonds in this salt are separeted because of heat: 
</span>NaI(l) → Na⁺(l) + I⁻(l).

Reaction of reduction at cathode(-): Na⁺(l) + e⁻ → Na(l) /×2.

2Na⁺(l) + 2e⁻ → 2Na(l).

Reaction of oxidation at anode(+): 2I⁻(l) → I₂(l) + 2e⁻.

The anode is positive and the cathode is negative.


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aleksandrvk [35]
Hello!

When aqueous solutions of Li₂SO₄ and NaI are mixed the following reaction occurs:

Li₂SO₄(aq) + 2NaI(aq) → 2LiI(aq) + Na₂SO₄(aq)

The compounds produced from this reaction are all soluble, so no precipitate is formed. We know that those compounds (LiI and Na₂SO₄) are soluble because of the solubility rules which states that salts from Group I elements (Li⁺, Na⁺) are soluble.

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4 0
4 years ago
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III) Fe^3+(aq) + 6CN^- -----------> [Fe(CN)6]^3- (aq) solubility increases

The ionic equations shown above shows the possible changes in solubility when Fe(OH)3 is added to each of the solutions mentioned in the question.

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