What is produced by AC and DC generators?

Which of the following statements are true of the horizontal motion of projectiles? List all that apply.a. A projectile does not

r-ruslan [8.4K]

Answer:

d. A projectile with a horizontal component of motion will have a constant horizontal velocity.

f. The horizontal velocity of a projectile is unaffected by the vertical velocity; these two components of motion are independent of each other.

g. The horizontal displacement of a projectile is dependent upon the time of flight and the initial horizontal velocity.

h. The final horizontal velocity of a projectile is always equal to the initial horizontal velocity.

Explanation:

When we are dealing with parabolic motion, the x-component of the velocity remains the same (hence, in the case of the horizontal component, the acceleration will always be zero), while the y-component always change because it is affected by the acceleration due gravity that acts verticaly.

On the other hand, the horizontal displacement $x$ of the projectile is mathematically expressed as:

$x=V_{ox} t$

Where:

$V_{ox}$ is the projectile's horizontal component of the initial velocity

$t$ is the time the parabolic motion lasts

This means the projectile's horizontal displacement is directly proportional to the horizontal component of the initial velocity and the total time the projectile describes the parabolic motion.

Of course, all of this considerations are assuming this is an ideal parabolic path and there is no air resistance.

5 0

4 years ago

The man is walking with speed v1 = 1.35 m/s to the right when he trips over a small floor discontinuity. Estimate his angular ve

soldier1979 [14.2K]

Answer:

The angular velocity, $\omega = 1.05 rad/s$ clockwise

Explanation:

The mass of the man, m = 72 kg

The center of mass of the man will be at the middle of his body, particularly around his abdomen.

Height of the center of mass, h = 0.71 m

The speed of the man, v₁ = 1.35 m/s

Moment of inertia about the ankle joint, I = 66 kg/m²

Based on the principle of conservation of angular momentum (about the ankle joint):

Angular momentum before impact = Angular momentum after impact

Angular momentum before impact = -mv₁h

Angular momentum before impact = -(72 * 1.35 * 0.71)

Angular momentum before impact = -69.012 kg m²/s...............(1)

Angular momentum after impact = $I \omega$

Angular momentum after impact = $66 * \omega$ .................(2)

$66 \omega = -69.012\\\omega = -69.012/66\\\omega = -1.05 rad/s$

The angular velocity, $\omega = 1.05 rad/s$ clockwise

8 0

3 years ago

A constant net torque is exerted on an object. Which of the following quantities for the object cannot be constant? (Select all

prohojiy [21]

Answer:

A. kinetic energy

B. angular velocity

E. angular position

Explanation:

The quantities that cannot be constant if a constant net torque is exerted on an objecta are:

A. Kinetic energy. If a torque is applied, the linear or angular speed will be changing at a rate proportional to the torque, so the kinetic energy will change too.

B. Angular velocity. It will change at a rate equal to the torque.

C. Angular position. If the angular velocity changes, the angular position will change.

3 0

4 years ago

Two friends, Barbara and Neil, are out rollerblading. With respect to the ground, Barbara is skating due south at a speed of 3.3

ozzi

Answer:

Answer is invalid make more sense next time please look it up somewhere else or ask somone smart. THere i gave you advice now i get points

Explanation:

8 0

4 years ago

An object is dropped from 42m tall building. How long does It take to reach the ground?