Answer:
She is likely to crash because her flight gradient is lesser than the flight gradient required gradient to avoid crashing
Explanation:
The given parameters are;
The required gradient of the plane Ashley is flying needs to reach in order to take off and not crash = 360 m/km
The initial elevation of the plane Ashley is flying = Sea level = 0 m
The goal Ashley intends to make = Elevation of 1000 m at 2.8 km. distance
∴ Ashley's goal = Traveling from sea level to 1000 m at 2.8 km horizontal distance
We have;
The gradient = Rate of change of elevation/(Horizontal distance)
Therefore;
The gradient of Ashley's flight = (1000 - 0)/(2.8 - 0) = 357.143 m/km
The gradient of Ashley's flight ≈ 357.143 m/km which is lesser than the required 360 m/km in order to take off and not crash, therefore, she will crash.
M = mass of the larger fish =5kg
<span>V = velocity of the larger fish =10m/s</span>
<span>m = mass of the smaller fish =2kg</span>
<span>v = velocity of the smaller fish =10m/s
</span>formula=
<span>MV = mv
5kg*10m/s=2kg*10m/s
biggern mass fish has more momentum
hope this helps
</span>
Answer:
The frequency increases.
Explanation:
When the Musician draws the slide in the length of the horn gets shorter, which causes a decrease in the wavelength. A decrease in the wave length results in an increase in frequency.
Note:
The diameter of the horn has an effect on frequency, so a wider horn is effectively a long horn - open end correction ( distance between the the antinode and the open end of a pipe).
Frequency also depends on how hard the musician blows the trombone. The musician can change the frequency with the lip pressure being applied.
Answer:
there is the increase the temperature of cold body and decrease the temperature of hot body
Answer:
The work done by gravity during the roll is 490.6 J
Explanation:
The work (W) is:
<em>Where</em>:
F: is the force
d: is the displacement = 20 m
The force is equal to the weight (W) in the x component:
<em>Where:</em>
m: is the mass of the bowling ball = 5 kg
g: is the gravity = 9.81 m/s²
θ: is the degree angle to the horizontal = 30°
Now, we can find the work:
Therefore, the work done by gravity during the roll is 490.6 J.
I hope it helps you!
