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3 years ago

Find the balance if $500 is invested earning 4% compounded monthly, after 6 years.

Mathematics

1 answer:

IceJOKER [234]3 years ago

8 0

Answer:

$636

dont trust me im just a 7th grader

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The slope of the line tangent to the curve y^2 + (xy+1)^3 = 0 at (2, -1) is ...?

Lina20 [59]

$\frac{d}{dx}(y^2 + (xy+1)^3 = 0)
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\\\frac{d}{dx}y^2 + \frac{d}{dx}(xy+1)^3 = \frac{d}{dx}0
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\\\frac{dy}{dx}2y + \frac{d}{dx}(xy+1)\ *3(xy+1)^2 = 0
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\\\frac{dy}{dx}2y + \left(\frac{d}{dx}(xy)+\frac{d}{dx}1\right)\ * 3(xy+1)^2 = 0
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\\\frac{dy}{dx}2y + \left(\frac{d}{dx}xy+x\frac{d}{dx}y+\frac{dx}{dx}\right)\ * 3(xy+1)^2 = 0
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\\\frac{dy}{dx}2y + \left(\frac{dx}{dx}y+x\frac{dy}{dx}+\frac{dx}{dx}0\right)\ * 3(xy+1)^2 = 0
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\\\frac{dy}{dx}2y + \left(y+x\frac{dy}{dx}\right)\ * 3(xy+1)^2 = 0$
$\frac{dy}{dx}2y + \left(y+x\frac{dy}{dx}\right)\ * 3(xy+1)^2 = 0
\\
\\\frac{dy}{dx}2y + \left(3y+3x\frac{dy}{dx}\right) (xy+1)^2 = 0
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\\2y\ y' + \left(3y+3x\ y'\right) (xy+1)^2 = 0
\\
\\2y\ y' + \left(3y+3x\ y'\right) ((xy)^2+2xy+1) = 0
\\
\\2y\ y' + \left(3y+3x\ y'\right) ((xy)^2+2xy+1) = 0
\\
\\2y\ y' + 3x^2y^3 +6xy^2+3y+(3x y' +6x^2y y'+3x^2y y') = 0
\\
\\3x^2y^3 +6xy^2+3y+(3x y' +6x^2y y'+3x^2y y'+2yy' ) = 0
\\
\\y'(3x +6x^2y+3x^2y+2y ) = -3x^2y^3 -6xy^2-3y

$
$y' = \frac{-3x^2y^3 -6xy^2-3y}{(3x +6x^2y+3x^2y+2y )};\ x=2,y=-1
\\
\\y' = \frac{-3(2)^2(-1)^3 -6(2)(-1)^2-3(-1)}{(3(2) +6(2)^2(-1)+3(2)^2(-1)+2(-1) )}
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\\y' = \frac{-3(4)(-1) -6(2)(1)+3}{(6 +6(4)(-1)+3(4)(-1)-2 )}
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\\y' = \frac{12 -12+3}{(6 -24-12-2 )}
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7 0

3 years ago

What is the scale factor to go from small triangle to the large triangle?

Elis [28]

Divide both numbers in one of the ratios by their highest common factor. This will give you the scale factor of the bigger triangle to the smaller triangle.

3 0

3 years ago

Find the range of possible values for the following measurements, which were rounded to the nearest mm, tenth of m, and hundredt

zmey [24]

The required range of the data is 24mm

The range of data is the difference between the largest value and the least value in a set of data.

Since we are not given the range of data. Let's assume we gave the following data:

34mm, 30mm, 20mm, 44mm, 31mm

From the data

Highest measurement = 44mm

Least measurement = 20mm

Find the range

Range = Highest measurement - Least measurement

Range = 44mm - 20mm

Range = 24mm

Hence the required range of data is 24mm

<em>NB: The concept can be applied to any set of data given for other measurements in (b) and (c)</em>

<em>Learn more here: brainly.com/question/1786006</em>

6 0

3 years ago

There are 4 times as many used cars in the car dealership lot as there as new cars. There are 120 cars total in the dealership l

jarptica [38.1K]

Answer:

120÷5=24 / 24×4=96 / 96+24=120

Step-by-step explanation:

3 0

3 years ago

4-7x +3 +5x pleas help thanks

meriva

Answer:

7−2x

Step-by-step explanation:

1 Collect like terms.

(4+3)+(-7x+5x)

(4+3)+(−7x+5x)

2 Simplify.

7-2x

7−2x

3 0

3 years ago

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