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vitfil [10]
3 years ago
12

In the same set of 1,000 integers from 1 to 1,000, an integer chosen at random on a single trial should be an integer from 1 to

25 about 25 out of every 1,000 trials, or one out of every 40 integers selected. How many integers between 1 and 25 would you expect to appear in a sample of 80 trials?
A. A sample of 80 integers would be expected to have no integers from 1 to 25.
B. A sample of 80 integers would be expected to have two integers from 1 to 25.
C. A sample of 80 integers would be expected to have four integers from 1 to 25.

Reminder: Don't post nonsense answer like "nweudnne" for points or ill do it right back at you and explain your answer.
Mathematics
1 answer:
uysha [10]3 years ago
8 0

Answer:

do u still need help

Step-by-step explanation:

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I need help plz help me
Marta_Voda [28]

Answer:

3000g

hope this helps

7 0
3 years ago
3) When Jackie took her children to the movie theater, she bought one box of candy and three small drinks for
Nezavi [6.7K]

Answer:

c + 3d = 14.75

2c + 5d = 26

A box of candy is $4.25 and a drink is $3.50

Step-by-step explanation:

Let c represent the cost of a box of candy and let d represent the cost of a drink

c + 3d = 14.75

2c + 5d = 26

Solve by elimination by multiplying the top equation by -2

-2c - 6d = -29.5

2c + 5d = 26

Add them together

-d = -3.5

d = 3.5

Plug in 3.5 as d into one of the equations to solve for c

c + 3d = 14.75

c + 3(3.5) = 14.75

c + 10.5 = 14.75

c = 4.25

So, a box of candy is $4.25 and a drink is $3.50

6 0
2 years ago
1.4t-0.4(t-3.1)=5.8 please help !!
Svetllana [295]
Okay so i cant just post what the answer is i have to type something.
but anyways this is the answer: t= 4.56
4 0
3 years ago
A snail can travel 390 inches in 5 hours.<br> How far does it travel in 1 hour?
puteri [66]
78, divide 390 by 5 which equals 78
8 0
2 years ago
Read 2 more answers
The ages of armadillos are normally distributed, with a mean of 14 years and a standard deviation of 1.2. Approximately what per
vovangra [49]

Answer:

Percentage of armadillos between 13 and 17 years = 79.052%f using Standard Normal Distribution Tables

Step-by-step explanation:

As we know from normal distribution: z(x) = (x - Mu)/SD

where x = targeted value; Mu = Mean of Normal Distribution; SD = Standard Deviation of Normal Distribution

Therefore using given data: Mu = 14, SD = 1.2 we have z(x) by using z(x) = (x - Mu)/SD as under:

Approach 1 using Standard Normal Distribution Table:

z for x=17: z(17) = (17-14)/1.2 gives us z(17) = 2.5

z for x=13: z(13) = (13-14)/1.2 gives us z(13) = -0.83

Afterwards using Normal Distribution Tables we find the probabilities as under:

P(17) using z(17) = 2.5 gives us P(17) = 99.379%

Similarly we have:

P(13) using z(13) = -0.83 gives us P(13) = 20.327%

Finally in order to find out the probability between 17 & 13 years we have:

Percentage of armadillos between 13 and 17 years = P(17) - P(13) = 99.379% - 20.327% = 79.052%

The standard normal distribution table is being attached for yours easiness.

Approach 2 using Excel or Google Sheets:

P(17) = norm.dist(17,14,1.2,1)

P(13) = norm.dist(13,14,1.2,1)

Percentage of armadillos between 13 and 17 years = { P(17) - P(13) } * 100

Download pdf
4 0
3 years ago
Read 2 more answers
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