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beks73 [17]
3 years ago
14

Which equation has infinitely many solutions?

Mathematics
1 answer:
Maru [420]3 years ago
4 0
For C and D do distributive
3x + 6 - 1 = 3x + 1
4x + 4 - 3 = 4x + 1
Only D is true

The solution is D
You might be interested in
In 2005, the Federal Aviation Administration (FAA) updated its passenger weight standards to an average of 190 pounds in the sum
Monica [59]

Answer: 0.0051

Step-by-step explanation:

Given the following :

Average Population weight (m) = 190

Population standard deviation (σ) = 35

Total weight of 25commuters (x) = 5200

Sample mean = 5200 /25 = 108

Sample standard deviation = standard error :

σ / √n = 35/√25 =

35/5 = 7

Zscore = (x - m) / standard error

Zscore = (208 - 190) / 7

Zscore = 18 / 7

= 2.57

P( Z > 2.57) = 1 - p(Z < 2.57)

P(z < 2.57) = 0.9949

1 - p(Z < 2.57) = 1 - 0.9949 = 0.0051

5 0
3 years ago
Please help with math!! Picture attached!!
jasenka [17]
In order from top to bottom.
perpendicular
zero slope
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constant rate of change
7 0
3 years ago
A particle is moving with the given data. find the position of the particle. a(t) = 13 sin(t) + 4 cos(t), s(0) = 0, s(2π) = 10
alekssr [168]

OK so we need to find the function v(t) which will tell us where the particle is at any given time.

We know that the derivative of distance is speed and the derivative of speed is acceleration.

In this case we need to work backwords and find the integrals.


a(t) = 13 sin(t) + 4 cos(t)

s(t)= integral of above = 13(-cos(t)) + 4(sin(t)) + C

v(t)= integral of above = -13sin(t) -4cos(t) +Ct + D


Now I believe you have incorrect initial conditions

s(0) = 0, s(2π) = 10

As cos and sin functions have the same value at 0 and 2Pi the above cannot be true.

My guess is that one is s(0) and the other is v(2Pi) or the other way round.

These initial conditions will determine the value of the two constants: C and D.


Hope this helps.

3 0
3 years ago
Which statement is true?
Lady_Fox [76]

Answer:

An irrational number may show terminating digits after the decimal

Step-by-step explanation:

Examples of Rational Numbers

Number 9 can be written as 9/1 where 9 and 1 both are integers.  0.5 can be written as ½, 5/10 or 10/20 and in the form of all termination decimals.  √81 is a rational number, as it can be simplified to 9 and can be expressed as 9/1.  0.7777777 is recurring decimals and is a rational number

Examples of Irrational Numbers

Similarly, as we have already defined that irrational numbers cannot be expressed in fraction or ratio form, let us understand the concepts with few examples.

5/0 is an irrational number, with the denominator as zero.

π is an irrational number which has value 3.142…and is a never-ending and non-repeating number.

√2 is an irrational number, as it cannot be simplified.

0.212112111…is a rational number as it is non-recurring and non-terminating.

There are a lot more examples apart from above-given examples, which differentiate rational numbers and irrational numbers.

Properties of Rational and Irrational Numbers

Here are some rules based on arithmetic operations such as addition and multiplication performed on the rational number and irrational number.

#Rule 1: The sum of two rational numbers is also rational.

Example: 1/2 + 1/3 = (3+2)/6 = 5/6

#Rule 2: The product of two rational number is rational.

Example: 1/2 x 1/3 = 1/6

#Rule 3: The sum of two irrational numbers is not always irrational.

Example: √2+√2 = 2√2 is irrational

2+2√5+(-2√5) = 2  is rational

#Rule 4: The product of two irrational numbers is not always irrational.

Example: √2 x √3 = √6 (Irrational)

√2 x √2 = √4 = 2 (Rational)

5 0
3 years ago
Multiply the rational expressions 2x^2 - 4x - 6 x^2 - 4 ——————- • ——————— x + 2 2x^2 + 2x
lorasvet [3.4K]

Answer:

C =(x-3)(x-2)/x

or

x²-5x+6/x

Step-by-step explanation:

2x^2 - 4x - 6/x + 2 * x^2 - 4/2x^2 + 2x

Factorizing the given factors

1) 2x^2 - 4x - 6

= 2x^2 - 6x+2x - 6

= 2x(x-3) +2(x-3)

= (x-3)(2x+2)

2) x^2 - 4

= (x+2) (x-2)

3) 2x^2 + 2x

= 2x( x+1)

Putting the factors

(x-3)(2x+2)/x + 2   *  (x+2) (x-2)/2x( x+1)

= (x-3)(2x+2) (x-2)/2x( x+1)

= 2(x-3)(x+1) (x-2)/2x( x+1)

=(x-3)(x-2)/x

Now multiply

(x-3)(x-2) =x²-5x+6

Then the answer becomes  x²-5x+6/x

8 0
3 years ago
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