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3 years ago

What is the value of x in the equation? 6(x +1) -5x = 8 + 2(x - 1)

Mathematics

2 answers:

Artyom0805 [142]3 years ago

7 0

Answer:

x = 0

Step-by-step explanation:

sineoko [7]3 years ago

4 0

Answer: x =0

Step-by-step explanation:

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Amy's yearly salary is given by the equation y = 25,000 + 700x, where x is the number of years since 2007 and y is her salary in

yanalaym [24]

2007 would be 0 years since 2007

y=25000+700(0)
y=25000

Answer: Her yearly salary in 2007 was $25,000

Hope this helps:)

3 0

4 years ago

Vilka [71]

Answer:

y=4

Step-by-step explanation:

7 0

3 years ago

If the original quantity is 10 and the new quantity is 6, what is percent increase

Ad libitum [116K]

Answer:

Using the percentage difference formula you can find the percentage decrease.

SO its

100(new-old/new)

So we solve

10-6=4

4/10= 2/5

2/5*100=200/5

40 percent decrease

3 0

2 years ago

Luana bought a new phone and plan. She paid $175. after three months, She paid $295. after 6 months. Write an equation that mode

elixir [45]

Answer: Hence, our required model will be

$C=40m+55$

Explanation:

Since we have given that

Luana bought a new phone and

For 3 months, the amount she paid = $175

For 6 months, the amount she paid = $295

Now, we have to model an equation ,

Here, let cost be 'C' and

Let number of months be 'm'.

So, we will use the "equation of line" i.e. for two point slope form :

Here y represented by 'C' and x represented by 'm'

So,

$C-C_0=\frac{295-175}{6-3}(m-m_0)\\\\C-175=\frac{120}{3}(m-3)\\\\C-175=40(m-3)\\\\C-175=40m-120\\\\C=40m-120+175\\\\C=40m+55$

Hence, our required model will be

$C=40m+55$

6 0

3 years ago

Graph the exponential function<img src="https://tex.z-dn.net/?f=%20f%28x%29%3D%5Cfrac%7B1%7D%7B2%7D%5E%7Bx%7D%20%20" id="TexForm

tatyana61 [14]

$f(x)=\left(\dfrac{1}{2}\right)^x\\\\for\ x=-3\to y=\left(\dfrac{1}{2}\right)^{-3}=2^3=8\to(-3,\ 8)\\\\for\ x=-2\to y=\left(\dfrac{1}{2}\right)^{-2}=2^2=4\to(-2,\ 4)\\\\for\ x=-1\to y=\left(\dfrac{1}{2}\right)^{-1}=2^1=2\to(-1,\ 2)\\\\for\ x=0\to y=\left(\dfrac{1}{2}\right)^0=1\to(0,\ 1)\\\\for\ x=1\to y=\left(\dfrac{1}{2}\right)^1=\dfrac{1}{2}\to\left(1,\ \dfrac{1}{2}\right)\\\\for\ x=2\to y=\left(\dfrac{1}{2}\right)^2=\dfrac{1}{4}$

3 0

3 years ago