Question

What is the value of sinθ given that (−6, −8) is a point on the terminal side of θ ?

Answer 1

Answer:

$\frac{-4}{5}$

Step-by-step explanation:

Let a=-8

b=-6

In triangle , by using Pythagoras theorem,

$r^{2}$=$a^{2}$+$b^{2}$

r=$\sqrt{a^2+b^{2}$

r=$\sqrt{(-8)^2+(-6)^{2}$

r=$\sqrt{64+36$

r=$\sqrt{100}$

r=10

by using trigonometric ratio,

sinθ =$\frac{a}{r}$

sinθ =$\frac{-8}{10}$

sinθ =$\frac{-4}{5}$

Answer 2

4/5 i think. use pythagorean theorem to find the length of the hypotenuse, and then from there you can find sin, because sin= opposite/hypotenuse. dont forget to reduce!!