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AlexFokin [52]
3 years ago
12

Samir and Christian had a total of 360 marbles Samir lost 28 marbles while Christian brought 18 more marbles both of them had an

equal number of marbles in the end how many marbles did Samir have at the beginning ​
Mathematics
2 answers:
klasskru [66]3 years ago
6 0

Step-by-step explanation:

Marbles altogether = 360

Marbles Samir Lost = 28

360 - 28 = 332

Marbles Christian bought 18

332 + 18 = 350

Marbles both had in the end = 350 ÷ 2 = 175

Marbles Samir have at the beginning = 175 + 28 = 203

Answer = 203

Musya8 [376]3 years ago
5 0
The answer to question is whether you want me some of your questions about the question of the answer to answer question i question is the B.
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A population of fish in a lake is 14000 in 2010. The population decreases 6% annually. What is the population in 2019
kodGreya [7K]

Answer:

8022.

Step-by-step explanation:

Let x be the number of years after 2010.

We have been given a population of fish in a lake is 14000 in 2010. The population decreases 6% annually.

We can see that population of fish is the lake is decreasing exponentially as it is decreasing 6% annually.

Since we know that an exponential function is in form: y=a*b^x, where,

a = Initial value,

b = For decrease or decay b is in form (1-r) where r represents decay rate in decimal form.

Let us convert our given decay rate in decimal form.

6\5=\frac{6}{100}=0.06

Upon substituting our given values in exponential form of function we will get the population of fish in the lake after x years as:

y=14,000*(1-0.06)^x

y=14,000*(0.94)^x

Let us find x by subtracting 2010 from 2019.

x=2019-2010=9

Upon substituting x=9 in our function we will get,

y=14,000*(0.94)^9

y=14,000*0.5729948022286167

y=8021.927\approx 8022

Therefore, the population of fish in 2019 will be 8022.

6 0
3 years ago
13x=-21-6y and -8x=36+6y
IgorLugansk [536]

Answer:

x=3\\y=-10

Step-by-step explanation:

13x=-21-6y\\-8x=36+6y

Let's take one of the equations and solve for x. I'll take the first one.

13x=-21-6y

Divide by 13.

x=\frac{-21-6y}{13}

Now replace x in the second equation.

-8x=36+6y\\-8(\frac{-21-6y}{13} )=36+6y

Distribute -8

\frac{168+48y}{13}=36+6y

Break down the fraction.

\frac{168}{13}+\frac{48}{13}y=36+6y

Subtract \frac{168}{13}

\frac{48}{13}y=36+6y-\frac{168}{13}

Subtract 6y

\frac{48}{13}y-6y=36-\frac{168}{13}

Combine like terms;

\frac{48-13*6}{13}y=\frac{36*13-168}{13}

Solve;

\frac{48-78}{13}y=\frac{468-168}{13}

Keep solving;

\frac{-30}{13}y=\frac{300}{13}

Multiply by the negative reciprocal of the fraction next to y.

(-\frac{13}{30} )\frac{-30}{13}y=\frac{300}{13}(-\frac{13}{30} )

On the right side; 13 and 13 become 1. 300/30 = 30/3 = 10

y=-10

After having found y, replace it in any of the equations to find x.

13x=-21-6y\\13x=-21-6(-10)\\13x=-21+60\\13x=39\\x=\frac{39}{13}\\ x=3

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3 years ago
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Answer:

x∈R

Step-by-step explanation:

y=2^{x}

2>0

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x∈R

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