Answer:
8022.
Step-by-step explanation:
Let x be the number of years after 2010.
We have been given a population of fish in a lake is 14000 in 2010. The population decreases 6% annually.
We can see that population of fish is the lake is decreasing exponentially as it is decreasing 6% annually.
Since we know that an exponential function is in form:
, where,
a = Initial value,
b = For decrease or decay b is in form (1-r) where r represents decay rate in decimal form.
Let us convert our given decay rate in decimal form.

Upon substituting our given values in exponential form of function we will get the population of fish in the lake after x years as:


Let us find x by subtracting 2010 from 2019.

Upon substituting x=9 in our function we will get,



Therefore, the population of fish in 2019 will be 8022.
Answer:

Step-by-step explanation:

Let's take one of the equations and solve for x. I'll take the first one.

Divide by 13.

Now replace x in the second equation.

Distribute -8

Break down the fraction.

Subtract 

Subtract 6y

Combine like terms;

Solve;

Keep solving;

Multiply by the negative reciprocal of the fraction next to y.

On the right side; 13 and 13 become 1. 300/30 = 30/3 = 10

After having found y, replace it in any of the equations to find x.

Answer:
x∈R
Step-by-step explanation:

2>0
The domain is all real numbers.
x∈R
Factors of 24.
1, 2, 3, 4, 6, 8, 12, and 24<span>. </span>
Terminal and Initial sides.