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What is the equation of the line parallel to y=-5x-9 and contains the point (-3, -3)?

First of all, parallel lines have the exact same slope.
So we know the slope of the line:- -5.
(enter -5, It's the number that belongs in the green box)
How about the y-intercept?
Well, since we're given the slope and a point that the line intersects, we can write the line's equation in point-slope form:-
y-y1=m(x-x1)
y-(-3)=-5(x-(-3)
y+3=-5(x+3)
y+3=-5x-15
y=-5x-18
<h3>Good luck.</h3>
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Answer:
a=2 and b=2...............
Answer:
see explanation
Step-by-step explanation:
Using the property of parallelograms
• The diagonals bisect each other, hence
DH = HF and GH = HE
x + 1 = 3y and 3x - 4 = 5y + 1 ⇒ 3x = 5y + 5
Solving the 2 equations simultaneously
x + 1 = 3y → (1)
3x = 5y + 5 → (2)
rearrange (1) expressing x in terms of y
x = 3y - 1 → (3)
substitute x = 3y - 1 in (2)
3(3y - 1) = 5y + 5
9y - 3 = 5y + 5 ( subtract 5y from both sides )
4y - 3 = 5 ( add 3 to both sides )
4y = 8 ( divide both sides by 4 )
y = 2
substitute y = 2 into (3)
x = (3 × 2) - 1 = 6 - 1 = 5
Hence x = 5, y = 2